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Figure 1 shows a sketch of the curve with equation $$y = \frac{2}{x}, \quad x \neq 0$$ The curve C has equation $$y = \frac{2}{x} - 5, \quad x \neq 0$$ and the line l has equation $$y = 4x + 2.$$ (a) Sketch and clearly label the graphs of C and l on a single diagram - Edexcel - A-Level Maths Pure - Question 7 - 2013 - Paper 3

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Question 7

Figure-1-shows-a-sketch-of-the-curve-with-equation-$$y-=-\frac{2}{x},-\quad-x-\neq-0$$--The-curve-C-has-equation-$$y-=-\frac{2}{x}---5,-\quad-x-\neq-0$$--and-the-line-l-has-equation-$$y-=-4x-+-2.$$----(a)-Sketch-and-clearly-label-the-graphs-of-C-and-l-on-a-single-diagram-Edexcel-A-Level Maths Pure-Question 7-2013-Paper 3.png

Figure 1 shows a sketch of the curve with equation $$y = \frac{2}{x}, \quad x \neq 0$$ The curve C has equation $$y = \frac{2}{x} - 5, \quad x \neq 0$$ and the lin... show full transcript

Worked Solution & Example Answer:Figure 1 shows a sketch of the curve with equation $$y = \frac{2}{x}, \quad x \neq 0$$ The curve C has equation $$y = \frac{2}{x} - 5, \quad x \neq 0$$ and the line l has equation $$y = 4x + 2.$$ (a) Sketch and clearly label the graphs of C and l on a single diagram - Edexcel - A-Level Maths Pure - Question 7 - 2013 - Paper 3

Step 1

Sketch and clearly label the graphs of C and l on a single diagram.

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Answer

  1. Sketch the curve C: Start by plotting the hyperbola defined by the equation y=2xy = \frac{2}{x}. The curve will approach the x-axis (y = 0) and y-axis (x = 0) as asymptotes.

  2. Shift the hyperbola: Since C’s equation is y=2x5y = \frac{2}{x} - 5, shift the entire hyperbola downward by 5 units. The new asymptote is now at y = -5.

  3. Sketch the line l: Draw the line given by the equation y=4x+2y = 4x + 2. This line has a y-intercept at (0, 2) and a slope of 4.

  4. Label axes crossings: Identify points where C crosses the x-axis (i.e., set y = 0) and where l crosses the axes. Ensure these points are marked clearly on the diagram.

Step 2

Write down the equations of the asymptotes of the curve C.

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Answer

The asymptotes for the curve C given by (y = \frac{2}{x} - 5) are:

  1. The vertical asymptote at (x = 0)
  2. The horizontal asymptote at (y = -5)

Step 3

Find the coordinates of the points of intersection of y = 2/x - 5 and y = 4x + 2.

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Answer

To find the points of intersection, set the equations equal:
2x5=4x+2\frac{2}{x} - 5 = 4x + 2

  1. Multiply through by x to eliminate the fraction:
    25x=4x2+2x2 - 5x = 4x^2 + 2x

  2. Rearranging gives:
    4x2+7x2=04x^2 + 7x - 2 = 0

  3. Use the quadratic formula to solve for x:
    x=b±b24ac2a=7±49+328=7±98x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} = \frac{-7 \pm \sqrt{49 + 32}}{8} = \frac{-7 \pm 9}{8}

  4. This gives two potential solutions:

    • (x = \frac{1}{4} \approx 0.25)
    • (x = -2)
  5. Now, substitute these x-values back into either original equations to obtain corresponding y-values:

    • For (x = \frac{1}{4}):
      y=4(14)+2=3y = 4\left(\frac{1}{4}\right) + 2 = 3
    • For (x = -2):
      y=4(2)+2=6y = 4(-2) + 2 = -6

The points of intersection are approximately (\left(\frac{1}{4}, 3\right)) and ((-2, -6)).

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