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Yuto works in the quality control department of a large company - Edexcel - A-Level Maths Statistics - Question 5 - 2017 - Paper 1

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Yuto works in the quality control department of a large company. The time, T minutes, it takes Yuto to analyse a sample is normally distributed with mean 18 minutes ... show full transcript

Worked Solution & Example Answer:Yuto works in the quality control department of a large company - Edexcel - A-Level Maths Statistics - Question 5 - 2017 - Paper 1

Step 1

Find the probability that Yuto takes longer than 20 minutes to analyse the next sample.

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Answer

To find the probability that Yuto takes longer than 20 minutes, we first standardize the variable.

Using the formula for standardization: z=Xμσz = \frac{X - \mu}{\sigma} where XX is the value we are interested in, μ \mu is the mean, and σ \sigma is the standard deviation.

For X=20X = 20, μ=18 \mu = 18, and σ=5 \sigma = 5, we have: z=20185=25=0.4z = \frac{20 - 18}{5} = \frac{2}{5} = 0.4

Now, we find the probability: P(T>20)=P(Z>0.4)=1P(Z0.4)P(T > 20) = P(Z > 0.4) = 1 - P(Z \leq 0.4) Using standard normal distribution tables or a calculator, we find: P(Z0.4)0.6554P(Z \leq 0.4) \approx 0.6554 Thus, P(T>20)=10.6554=0.3446P(T > 20) = 1 - 0.6554 = 0.3446

Step 2

Find the probability that this sample took Yuto more than 20 minutes to analyse.

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Answer

For a sample that took Yuto longer than 15 minutes, we need to calculate the conditional probability: P(T>20T>15)=P(T>20)P(T>15)P(T > 20 | T > 15) = \frac{P(T > 20)}{P(T > 15)} We already calculated P(T>20)=0.3446P(T > 20) = 0.3446.

Next, we calculate P(T>15)P(T > 15):

$$P(T > 15) = 1 - P(Z \leq -0.6) \approx 1 - 0.2743 = 0.7257$$ Now, substituting: $$P(T > 20 | T > 15) = \frac{0.3446}{0.7257} \approx 0.4745$$

Step 3

Estimate the median time taken by Yuto to analyse samples in future.

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Answer

For a normal distribution, the median is equal to the mean. Therefore, the median time taken by Yuto to analyse samples in the future can be estimated as: Median=μ=18Median = \mu = 18 It can also be noted that the median time taken could be approximated, and might vary slightly based on future performance, but based on current data, it's safe to estimate:

Estimated Median = 19.8 minutes

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