Dian uses the large data set to investigate the Daily Total Rainfall, r mm, for Camborne - Edexcel - A-Level Maths Statistics - Question 3 - 2022 - Paper 1
Question 3
Dian uses the large data set to investigate the Daily Total Rainfall, r mm, for Camborne.
(a) Write down how a value of $0 < r ext{ } ext{ } ext{ } ext{ } ext{... show full transcript
Worked Solution & Example Answer:Dian uses the large data set to investigate the Daily Total Rainfall, r mm, for Camborne - Edexcel - A-Level Maths Statistics - Question 3 - 2022 - Paper 1
Step 1
Write down how a value of $0 < r < 0.05$ is recorded in the large data set.
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Answer
In the large data set, a value of 0<r<0.05 is recorded as '0 mm'. This indicates that there was some recorded precipitation, but the amount was negligible and falls below the threshold for measurement.
Step 2
the mean of the Daily Total Rainfall in Camborne for August 2015.
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To calculate the mean Daily Total Rainfall, we can use the formula:
the standard deviation of the Daily Total Rainfall in Camborne for August 2015.
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The standard deviation can be calculated using the formula:
ext{s} = rac{ ext{squared sum of residuals}}{n - 1}
where the squared sum is given by
ext{Var} = rac{3532.283}{31} - (5.64)^2 \approx 9.19
Thus,
exts=extsqrt(9.19)extwhichisapproximately3.02 mm.
Step 4
State, giving a reason, whether this provides evidence to support Dian's belief.
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Dian's belief is that the daily rainfall in the south is less than in the north. Observing that Leuchars has a mean rainfall of 1.72 mm suggests the mean rainfall in the south is indeed lower than the mean in Camborne (5.64 mm), but the evidence is not definitive as local variations can occur. Therefore, while it does provide some support, it is not conclusive.
Step 5
Explain why the distribution B(14, 0.27) might not be a reasonable model for the number of days without rain for a 14-day summer event.
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The binomial distribution B(14, 0.27) relies on the assumption that each day is an independent trial with the same probability of no rain, which might not hold in a summer period. Weather patterns may create dependencies between consecutive days, and the probability 0.27 itself may not accurately reflect the daily likelihood for specific local conditions in summer.