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A student investigated how the current in a filament lamp varies with the potential difference across the lamp - AQA - GCSE Physics - Question 1 - 2023 - Paper 1

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A student investigated how the current in a filament lamp varies with the potential difference across the lamp. Figure 1 shows the circuit used. 1. What is componen... show full transcript

Worked Solution & Example Answer:A student investigated how the current in a filament lamp varies with the potential difference across the lamp - AQA - GCSE Physics - Question 1 - 2023 - Paper 1

Step 1

What is component P?

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Answer

Component P is a switch.

Step 2

Complete the sentences.

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Answer

Current Potential difference

Step 3

How will increasing the resistance of the variable resistor in Figure 1 affect each of the following quantities?

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Answer

QuantityDecreasesStays the sameIncreases
Current in the circuit
Potential difference across the lamp
Total resistance of the circuit

Step 4

Calculate the current in the lamp.

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Answer

Using the given formula:

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current=charge flowtime=15 coulombs60 seconds=0.25 Acurrent = \frac{charge\ flow}{time} = \frac{15\ coulombs}{60\ seconds} = 0.25\ A

Current = 0.25 A

Step 5

Calculate the resistance of the filament lamp.

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Answer

Using the resistance formula:

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resistance=potential differencecurrent=6.0 V0.12 A=50 Ωresistance = \frac{potential\ difference}{current} = \frac{6.0\ V}{0.12\ A} = 50\ Ω

Resistance = 50 Ω

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