4 (a) Complete the table of values for $y = 5 - x^2$
| x | -2 | -1 | 0 | 1 | 2 |
|----|----|----|---|---|---|
| y | | | | | |
(b) On the grid below, draw the graph of $y = 5 - x^2$ for values of x from -2 to 2. - Edexcel - GCSE Maths - Question 4 - 2020 - Paper 2
Question 4
4 (a) Complete the table of values for $y = 5 - x^2$
| x | -2 | -1 | 0 | 1 | 2 |
|----|----|----|---|---|---|
| y | | | | | |
(b) On the grid below, ... show full transcript
Worked Solution & Example Answer:4 (a) Complete the table of values for $y = 5 - x^2$
| x | -2 | -1 | 0 | 1 | 2 |
|----|----|----|---|---|---|
| y | | | | | |
(b) On the grid below, draw the graph of $y = 5 - x^2$ for values of x from -2 to 2. - Edexcel - GCSE Maths - Question 4 - 2020 - Paper 2
Step 1
Complete the table of values for $y = 5 - x^2$
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Answer
To find the values of y for each corresponding value of x, we will substitute each x into the equation.
For x=−2: y=5−(−2)2=5−4=1
For x=−1: y=5−(−1)2=5−1=4
For x=0: y=5−02=5−0=5
For x=1: y=5−12=5−1=4
For x=2: y=5−22=5−4=1
The completed table is:
x
-2
-1
0
1
2
y
1
4
5
4
1
Step 2
On the grid below, draw the graph of $y = 5 - x^2$ for values of x from -2 to 2.
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Answer
To draw the graph of y=5−x2, we will plot the points obtained from the table:
For x=−2, y=1 (point: (-2, 1))
For x=−1, y=4 (point: (-1, 4))
For x=0, y=5 (point: (0, 5))
For x=1, y=4 (point: (1, 4))
For x=2, y=1 (point: (2, 1))
After plotting these points on the graph, connect them with a smooth curve to represent the quadratic function. The resulting graph will be a downward-opening parabola centered at (0,5), intersecting the y-axis at y=5.
