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The table gives information about the times taken, in seconds, by 18 students to run a race - Edexcel - GCSE Maths - Question 5 - 2019 - Paper 3

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The table gives information about the times taken, in seconds, by 18 students to run a race. | Time (s) | Frequency | | ------------ | --------- | | 5 < t ≤ 10 ... show full transcript

Worked Solution & Example Answer:The table gives information about the times taken, in seconds, by 18 students to run a race - Edexcel - GCSE Maths - Question 5 - 2019 - Paper 3

Step 1

Step 1: Calculate Midpoints

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Answer

To estimate the mean time, first, we need to calculate the midpoints for each time interval:

  • For the interval 5<t105 < t \leq 10: midpoint = ( \frac{5 + 10}{2} = 7.5 )
  • For the interval 10<t1510 < t \leq 15: midpoint = ( \frac{10 + 15}{2} = 12.5 )
  • For the interval 15<t2015 < t \leq 20: midpoint = ( \frac{15 + 20}{2} = 17.5 )
  • For the interval 20<t2520 < t \leq 25: midpoint = ( \frac{20 + 25}{2} = 22.5 )

Step 2

Step 2: Multiply Midpoints by Frequencies

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Answer

Next, we multiply each midpoint by its corresponding frequency:

  • 7.5×1=7.57.5 \times 1 = 7.5
  • 12.5×2=2512.5 \times 2 = 25
  • 17.5×7=122.517.5 \times 7 = 122.5
  • 22.5×8=18022.5 \times 8 = 180

Step 3

Step 3: Sum of Products and Frequencies

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Now, we sum these products:

[ 7.5 + 25 + 122.5 + 180 = 335 ]

And also sum the frequencies:

[ 1 + 2 + 7 + 8 = 18 ]

Step 4

Step 4: Calculate the Mean

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The estimated mean time is given by the formula:

[ \text{Mean} = \frac{\text{Total of products}}{\text{Total frequency}} = \frac{335}{18} \approx 18.61 ]

Rounding this to 3 significant figures gives us:

Mean time = 18.6 seconds

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