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Here is the graph of $y = sin \, x^2$ for $-180 \leq x \leq 180$ - Edexcel - GCSE Maths - Question 18 - 2018 - Paper 1

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Question 18

Here-is-the-graph-of--$y-=-sin-\,-x^2$-for-$-180-\leq-x-\leq-180$-Edexcel-GCSE Maths-Question 18-2018-Paper 1.png

Here is the graph of $y = sin \, x^2$ for $-180 \leq x \leq 180$. On the grid, sketch the graph of $y = sin \, x^2 - 2$ for $-180 \leq x \leq 180$.

Worked Solution & Example Answer:Here is the graph of $y = sin \, x^2$ for $-180 \leq x \leq 180$ - Edexcel - GCSE Maths - Question 18 - 2018 - Paper 1

Step 1

Sketch the Graph for $y = sin \, x^2 - 2$

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Answer

  1. Understanding the Transformation: The equation y=sinx22y = sin \, x^2 - 2 indicates a vertical shift of the graph of y=sinx2y = sin \, x^2 by -2 units. This implies that every point on the original graph will be lowered by 2 units.

  2. Determine Key Points: Start by noting some key values of the original graph. Since sinx2sin \, x^2 oscillates between -1 and 1, the function y=sinx2y = sin \, x^2 achieves its maximum value of 1 at certain points and minimum value of -1 at others. Those transitions will occur periodically based on x2x^2.

  3. Shifting the Graph: By lowering the entire graph of y=sinx2y = sin \, x^2 by 2 units, the maximum point will now be at y=12=1y = 1 - 2 = -1 and the minimum will be at y=12=3y = -1 - 2 = -3.

  4. Plotting the New Points: Begin plotting the new key points across the interval 180x180-180 \leq x \leq 180. Use known values of xx for which x2x^2 is a multiple of π2\frac{\pi}{2} to find the corresponding points on the original and transformed graphs.

  5. Final Sketch: Finally, connect these key points smoothly, maintaining the sinusoidal nature of the graph while ensuring that the entire graph is presented below the y-axis since the maximum is at -1 and the minimum at -3.

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