Sam and Joe are on their bikes. They are on a flat, straight road. (a) Joe is stationary when Sam rides past at a constant velocity of 10 m/s. Joe waits for 4 s and then follows Sam. This is a velocity/time graph of their motion. How far did Sam travel during these 15 s? distance = velocity x time Put a cross (✗) in the box next to your answer. A 1.5 m B 10 m C 100 m D 150 m

GCSE Edexcel Physics Velocity-time graphs: Sam and Joe are on their bikes.

To determine the distance Sam traveled during the 15 seconds, we need to analyze the velocity/time graph provided.

Establish the Conditions: From the graph, Sam rides at a constant velocity of 10 m/s after Joe waits for 4 seconds. So, for the first 4 seconds, Sam is moving at this velocity.
Calculate Distance for First 4 seconds: The distance Sam travels in this time can be calculated using the formula:

$ext{Distance} = ext{Velocity} imes ext{Time}$

For the first 4 seconds:

$ext{Distance} = 10 ext{ m/s} imes 4 ext{ s} = 40 ext{ m}$
Time Remaining: After the first 4 seconds, there are another 11 seconds to consider (15 s - 4 s).
Assuming Constant Velocity: Since Sam continues to travel at 10 m/s until the 15 seconds are complete:

For the remaining 11 seconds:

$ext{Distance} = 10 ext{ m/s} imes 11 ext{ s} = 110 ext{ m}$
Total Distance: Add the distances from both segments:

$ext{Total Distance} = 40 ext{ m} + 110 ext{ m} = 150 ext{ m}$

Hence, the distance Sam traveled during the 15 seconds is 150 m, which corresponds to answer choice D.