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Scalars and vectors Simplified Revision Notes

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4.1.1 Scalars and vectors

In physics, quantities can be classified as scalars or vectors:

  • Scalars have only magnitude (size) and no direction. Examples include distance, speed, mass, and temperature.
  • Vectors have both magnitude and direction. Examples include displacement, velocity, force (or weight), and acceleration.

Adding Vectors

There are two main methods to add vectors, depending on their orientation:

  1. Calculation Method (for Perpendicular Vectors):
  • When vectors are perpendicular to each other, you can use Pythagoras' theorem to find the resultant vector's magnitude and trigonometry to determine its direction.
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Example:

  • Two forces of 5 N5\ N and 12 N12\ N act perpendicular to each other. To find the resultant force RR :
R=122+52=13NR = \sqrt{12^2 + 5^2} = 13 \, \text{N}
  • To find the angle θ\theta from the horizontal:
tanθ=512θ=22.6\tan \theta = \frac{5}{12} \Rightarrow \theta = 22.6^\circ
  • Resultant Direction: 22.622.6^\circ from the horizontal.
image
  1. Scale Drawing (for Non-Perpendicular Vectors):
  • For vectors at arbitrary angles, use a scale diagram. Draw each vector to scale, using a ruler and protractor, then measure the resultant vector's magnitude and direction.
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Example:

  • A ship travels 3030 m at a bearing of 060°060°, then 2020 m east.
  • Draw a scale diagram.
  • Measure the resultant displacement's magnitude and angle.
image

Resolving Vectors

The process of breaking a vector into its horizontal and vertical components is called resolving. This is useful for analysing forces in different directions.

For a vector VV at an angle θ\theta :

  • Horizontal Component: x=Vcosθx = V \cos \theta
  • Vertical Component: y=Vsinθy = V \sin \theta Tip: If moving through the angle to reach the component, use cos. If moving away from the angle, use sin.
image
lightbulbExample

Example:

  • A ball is projected at 10 m/s10 \text{ m/s} at 3030^\circ :
x=10cos30=8.7m/sx = 10 \cos 30^\circ = 8.7 \, \text{m/s} y=10sin30=5m/sy = 10 \sin 30^\circ = 5 \, \text{m/s}
image
lightbulbExample

Example: Resolving Forces on an Inclined Plane For an object on a slope inclined at 1515^\circ:

  • If the object has a weight of 5050 N:
  • Component parallel to the plane: 50sin15=12.9N50 \sin 15^\circ = 12.9 \, \text{N}
  • Component perpendicular to the plane: 50cos15=48.3N50 \cos 15^\circ = 48.3 \, \text{N}
image

Equilibrium and Vector Triangles

An object is in equilibrium if the sum of all forces acting on it is zero, meaning it has no resultant force and remains at rest or in uniform motion (Newton's First Law).

To show equilibrium:

  • Add horizontal and vertical components of forces to check if they balance.
  • For three forces, draw a scale triangle: if it forms a closed triangle, the object is in equilibrium.
infoNote

Key Points

  1. Scalars vs. Vectors: Scalars have magnitude only; vectors have both magnitude and direction.
  2. Adding Vectors:
  • Use Pythagoras and trigonometry for perpendicular vectors.
  • Use a scale diagram for non-perpendicular vectors.
  1. Resolving Vectors: Break vectors into horizontal and vertical components using trigonometry.
  2. Equilibrium: Occurs when forces balance, shown by a closed triangle or zero net components.
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