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John is three times as old as Mary - Junior Cycle Mathematics - Question 10 - 2014

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John is three times as old as Mary. Mary's age in years is represented by x. Select one expression from A, B, C, D and E below which represents John's age in years. ... show full transcript

Worked Solution & Example Answer:John is three times as old as Mary - Junior Cycle Mathematics - Question 10 - 2014

Step 1

Select one expression from A, B, C, D and E below which represents John's age in years.

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Answer

Mary's age is x, therefore John's age is represented by 3x3x.

Step 2

Select one expression from A, B, C, D and E above which represents John's age in 3 years’ time.

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Answer

John's current age is 3x3x, thus in three years, his age will be 3x+33x + 3, which corresponds to expression C.

Step 3

Select one expression from A, B, C, D and E which represents Mary's age in 3 years’ time.

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Answer

Currently, Mary's age is represented by xx, so in three years, her age will be x+3x + 3, corresponding to expression A.

Step 4

In three years, John's age added to Mary's age will give a total of 26 years. Write down an equation in x to represent this statement.

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Answer

We can set up the equation:

(3x+3)+(x+3)=26(3x + 3) + (x + 3) = 26

This simplifies to 4x+6=264x + 6 = 26.

Step 5

Solve your equation to find Mary's present age.

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Answer

To solve the equation:

4x+6=264x + 6 = 26

Subtract 6 from both sides:

4x=204x = 20

Now, divide by 4:

x=5x = 5

Thus, Mary's present age is 5 years old.

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