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Write each of the following in the form $2^n$, where $n \in \mathbb{Q}$ - Junior Cycle Mathematics - Question 10 - 2016

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Question 10

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Write each of the following in the form $2^n$, where $n \in \mathbb{Q}$. (a) $2^3 \times 2^5 \times 2^{10}$ (b) $8^{25}$ (c) $\sqrt{8}$

Worked Solution & Example Answer:Write each of the following in the form $2^n$, where $n \in \mathbb{Q}$ - Junior Cycle Mathematics - Question 10 - 2016

Step 1

(a) $2^3 \times 2^5 \times 2^{10}$

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Answer

To simplify the expression, we use the property of exponents that states am×an=am+na^m \times a^n = a^{m+n}. Thus, we have:

23×25×210=23+5+10=218.2^3 \times 2^5 \times 2^{10} = 2^{3+5+10} = 2^{18}.

Therefore, the final answer is 2182^{18}.

Step 2

(b) $8^{25}$

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Answer

We can express 8 as a power of 2: 8=238 = 2^3. Hence, we rewrite 8258^{25}:

825=(23)25.8^{25} = (2^3)^{25}.

Applying the power of a power rule, (am)n=am×n(a^m)^n = a^{m \times n}, we get:

(23)25=23×25=275.(2^3)^{25} = 2^{3 \times 25} = 2^{75}.

Thus the answer is 2752^{75}.

Step 3

(c) $\sqrt{8}$

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Answer

To simplify 8 \sqrt{8}, we recall that a=a1/2 \sqrt{a} = a^{1/2}. We can express 8 as 8=238 = 2^3, so:

8=(23)=(23)1/2.\sqrt{8} = \sqrt{(2^3)} = (2^3)^{1/2}.

Utilizing the power of a power rule:

(23)1/2=23×12=232.(2^3)^{1/2} = 2^{3 \times \frac{1}{2}} = 2^{\frac{3}{2}}.

Therefore, the answer is 2322^{\frac{3}{2}}.

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