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Question 12 (a) Factorise $a^2 - 16n^2$ - Junior Cycle Mathematics - Question 12 - 2019

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Question 12 (a) Factorise $a^2 - 16n^2$. (b) One of the factors of $8x^2 + 45x - 18$ is $x + 6$. (i) Factorise $8x^2 + 45x - 18$. (ii) Write down one quadratic ex... show full transcript

Worked Solution & Example Answer:Question 12 (a) Factorise $a^2 - 16n^2$ - Junior Cycle Mathematics - Question 12 - 2019

Step 1

Factorise $a^2 - 16n^2$

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Answer

To factorise the expression a216n2a^2 - 16n^2, we recognize it as a difference of squares. This can be expressed as:

a2(4n)2=(a4n)(a+4n)a^2 - (4n)^2 = (a - 4n)(a + 4n)

Step 2

Factorise $8x^2 + 45x - 18$

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To factorise 8x2+45x188x^2 + 45x - 18, we will find two numbers that multiply to the product of the coefficient of x2x^2 and the constant term, which is 8×(18)=1448 \times (-18) = -144, while also adding up to the coefficient of xx, which is 4545.

After analyzing factors, we find:

8x2+48x3x188x^2 + 48x - 3x - 18

Now, we can group:

=8x(x+6)3(x+6)= 8x(x + 6) - 3(x + 6)

Factoring out the common term (x+6)(x + 6) gives us:

=(8x3)(x+6)= (8x - 3)(x + 6)

Step 3

Write down one quadratic expression in $x$, other than $8x^2 + 45x - 18$, that has $x + 6$ as a factor

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Consider the expression (x+6)(x+1)(x + 6)(x + 1). This expands to:

x2+7x+6x^2 + 7x + 6

In the required form, we have:

a=1,b=7,c=6a = 1, b = 7, c = 6

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