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Some students are asked to write down linear and quadratic expressions that have $(x + 2)$ as a factor - Junior Cycle Mathematics - Question 13 - 2014

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Question 13

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Some students are asked to write down linear and quadratic expressions that have $(x + 2)$ as a factor. (a) The expressions $3x + 5$, $x + 1$, and $2x - 10$ are exa... show full transcript

Worked Solution & Example Answer:Some students are asked to write down linear and quadratic expressions that have $(x + 2)$ as a factor - Junior Cycle Mathematics - Question 13 - 2014

Step 1

Write down a linear expression in $x$, other than $x + 2$, that has $x + 2$ as a factor.

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Answer

One possible linear expression is 2x+4=2(x+2)2x + 4 = 2(x + 2), which includes x+2x + 2 as a factor.

Step 2

For what value of $k$ will Anton's expression have $x + 2$ as a factor?

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Answer

In the expression x2kx^2 - k, to have x+2x + 2 as a factor, we can rewrite it using the difference of squares:

oot1{4})(x + oot1{4})$$ Thus, we find that $k = 4$.

Step 3

Find Denise's expression.

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Answer

Using the multiplication, we have:

(x+2)(2x+3)=x(2x+3)+2(2x+3)(x + 2)(2x + 3) = x(2x + 3) + 2(2x + 3) =2x2+3x+4x+6= 2x^2 + 3x + 4x + 6 =2x2+7x+6= 2x^2 + 7x + 6

So, Denise's expression is 2x2+7x+62x^2 + 7x + 6.

Step 4

Explain how division will allow her to check if $x + 2$ is a factor.

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Answer

If x+2x + 2 is a factor of the polynomial 3x2+11x+103x^2 + 11x + 10, the polynomial should divide evenly by x+2x + 2, resulting in no remainder. If the remainder is 0, then x+2x + 2 is indeed a factor.

Step 5

Divide $3x^2 + 11x + 10$ by $x + 2$.

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Answer

Performing synthetic or polynomial division gives:

  1. Divide the leading term: 3x2/x=3x3x^2 / x = 3x.
  2. Multiply back: 3x(x+2)=3x2+6x3x(x + 2) = 3x^2 + 6x.
  3. Subtract: (3x2+11x+10)(3x2+6x)=5x+10(3x^2 + 11x + 10) - (3x^2 + 6x) = 5x + 10.
  4. Next, divide 5x+105x + 10 by x+2x + 2: 55. The result is 3x+53x + 5 with a remainder of 00. Therefore, 3x2+11x+10=(x+2)(3x+5)3x^2 + 11x + 10 = (x + 2)(3x + 5).

Step 6

Write down one quadratic expression, other than those already given above, that has $x + 2$ as a factor.

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Answer

A quadratic expression that has x+2x + 2 as a factor could be obtained by multiplying x+2x + 2 by another linear expression, for example,

(x+2)(x+1)=x2+3x+2(x + 2)(x + 1) = x^2 + 3x + 2.

This gives the quadratic x2+3x+2x^2 + 3x + 2, which has x+2x + 2 as a factor.

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