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Find the value of \( \frac{2n+1}{3n-2} \) when \( n = 4 \) - Junior Cycle Mathematics - Question 8 - 2017

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Find the value of \( \frac{2n+1}{3n-2} \) when \( n = 4 \). Multiply out and simplify \( (w + 4)(3w - 2) \).

Worked Solution & Example Answer:Find the value of \( \frac{2n+1}{3n-2} \) when \( n = 4 \) - Junior Cycle Mathematics - Question 8 - 2017

Step 1

Find the value of \( \frac{2n+1}{3n-2} \) when \( n = 4 \)

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Answer

To find the value of ( \frac{2n+1}{3n-2} ) when ( n = 4 ), substitute ( n = 4 ) into the expression:

  1. Calculate the numerator: [ 2(4) + 1 = 8 + 1 = 9 ]

  2. Calculate the denominator: [ 3(4) - 2 = 12 - 2 = 10 ]

  3. Now, substitute these values into the fraction: [ \frac{9}{10} ]

Thus, the answer is ( \frac{9}{10} ).

Step 2

Multiply out and simplify \( (w + 4)(3w - 2) \)

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Answer

Using the distributive property (also known as the FOIL method for binomials):

  1. Multiply the first terms: [ w \cdot 3w = 3w^2 ]

  2. Multiply the outer terms: [ w \cdot (-2) = -2w ]

  3. Multiply the inner terms: [ 4 \cdot 3w = 12w ]

  4. Multiply the last terms: [ 4 \cdot (-2) = -8 ]

Now, combine all these results: [ 3w^2 + 12w - 2w - 8 = 3w^2 + 10w - 8 ]

Thus, the simplified expression is ( 3w^2 + 10w - 8 ).

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