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Orla has an eReader - Junior Cycle Mathematics - Question 4 - 2016

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Orla has an eReader. The front of the eReader is in the shape of a rectangle measuring 11 cm by 16 cm. It has a rectangular screen measuring 9 cm by 14 cm. (a) Work... show full transcript

Worked Solution & Example Answer:Orla has an eReader - Junior Cycle Mathematics - Question 4 - 2016

Step 1

Work out the area of the screen of Orla's eReader.

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Answer

To calculate the area of the screen, use the formula for the area of a rectangle:

extArea=extlengthimesextwidth ext{Area} = ext{length} imes ext{width}

Substituting the values for the screen:

extArea=9extcmimes14extcm=126extcm2 ext{Area} = 9 ext{ cm} imes 14 ext{ cm} = 126 ext{ cm}^2

Thus, the area of the screen is 126 cm².

Step 2

Is Orla correct? Justify your answer fully.

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Answer

To determine if the screen covers more than 80% of the area of the front of the eReader, we first need the area of the front:

extArea=11extcmimes16extcm=176extcm2 ext{Area} = 11 ext{ cm} imes 16 ext{ cm} = 176 ext{ cm}^2

Now, to find 80% of this area:

80 ext{% of Area} = 0.8 imes 176 ext{ cm}^2 = 140.8 ext{ cm}^2

Next, we compare the area of the screen (126 cm²) to 80% of the area of the front:

  • The area of the screen is 126 cm², which is less than 140.8 cm².

Therefore, since 126 cm² < 140.8 cm², Orla's statement is incorrect. The screen does not cover more than 80% of the area of the front of the eReader.

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