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The quadrilateral ABCD is shown in the co-ordinate diagram below - Junior Cycle Mathematics - Question 11 - 2021

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Question 11

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The quadrilateral ABCD is shown in the co-ordinate diagram below. (a) Complete the table below to show the co-ordinates of the four corners of ABCD. Point A ... show full transcript

Worked Solution & Example Answer:The quadrilateral ABCD is shown in the co-ordinate diagram below - Junior Cycle Mathematics - Question 11 - 2021

Step 1

Complete the table below to show the co-ordinates of the four corners of ABCD.

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Answer

The co-ordinates for points A, B, C, and D are as follows:

  • A (2, 4)
  • B (2, 0)
  • C (8, 0)
  • D (8, 4)

Step 2

On the diagram above, draw the image of ABCD under axial symmetry in the x-axis.

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Answer

To draw the image of ABCD under axial symmetry in the x-axis, reflect each point over the x-axis:

  • A (2, 4) becomes A' (2, -4)
  • B (2, 0) becomes B' (2, 0)
  • C (8, 0) becomes C' (8, 0)
  • D (8, 4) becomes D' (8, -4)

Plot these points on the diagram.

Step 3

Work out the area of the shape ABCD.

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Answer

To find the area of quadrilateral ABCD, it can be divided into a rectangle and a triangle.

  1. Rectangle ABCD:

    • Length = |x_D - x_A| = |8 - 2| = 6
    • Height = |y_A - y_B| = |4 - 0| = 4
    • Area = Length × Height = 6 × 4 = 24
  2. The area of the rectangle ABCD is:

    • Area = 24 square units.

Step 4

Write each line segment from the list above into the correct place in the table below, to match each line segment to its equation.

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Answer

The equations corresponding to each line segment are as follows:

  • [AB]: y = 4 (horizontal line at y = 4)
  • [BC]: y = 0 (horizontal line at y = 0)
  • [CD]: y = x - 7 (diagonal line segment)
  • [AD]: x = 8 (vertical line at x = 8)

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