The perimeter of a rectangle is 28 cm. The length of the rectangle is 9 cm. Find the width of the rectangle. The symbol for the Olympic Games is five intersecting rings. The rings represent the five continents which compete in the games. The radius of each ring is 4 m. Find the total circumference of the five rings. Use π = 3.142.

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The perimeter of a rectangle is 28 cm - Junior Cycle Mathematics - Question 7 - 2013

Question 7

The perimeter of a rectangle is 28 cm. The length of the rectangle is 9 cm. Find the width of the rectangle. The symbol for the Olympic Games is five intersecting r... show full transcript

Worked Solution & Example Answer:The perimeter of a rectangle is 28 cm - Junior Cycle Mathematics - Question 7 - 2013

Step 1

Find the width of the rectangle.

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Answer

To find the width of the rectangle, we start with the formula for the perimeter of a rectangle:

$P = 2(l + w)$

Given that the perimeter (P) is 28 cm and the length (l) is 9 cm, we can set up the equation:

$2(9 + w) = 28$

Next, simplify this equation:

Divide both sides by 2: $9 + w = 14$
Subtract 9 from both sides: $w = 14 - 9$
Therefore, the width (w) is: $w = 5 ext{ cm}$

Step 2

Find the total circumference of the five rings.

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Answer

The circumference of one ring can be calculated using the formula:

$C = 2 heta r$

where θ is the number of rings and r is the radius of each ring. Given that the radius is 4 m:

Calculate the circumference of one ring: $C = 2 imes 3.142 imes 4$
Then for five rings, multiply by 5: $ext{Total Circumference} = 5 imes C$ $= 5 imes (2 imes 3.142 imes 4)$ $= 125.68 ext{ m}$

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