Ruiari has a weekend job - Junior Cycle Mathematics - Question Q11 - 2011
Question Q11
Ruiari has a weekend job. His total pay per day is a fixed rate plus tips. The tips are a percentage of the customer spend.
The graph below shows Ruiari's total pay... show full transcript
Worked Solution & Example Answer:Ruiari has a weekend job - Junior Cycle Mathematics - Question Q11 - 2011
Step 1
What is Ruiari's fixed rate per day (his pay when the customer spend is €0)?
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Answer
Ruiari's fixed rate per day is €80. This is the pay he receives when there is no customer spend.
Step 2
What was Ruiari's total pay on that day?
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Answer
To find Ruiari's total pay on the day when the customer spend was €500 (so S = 5), we can use the equation referring to his pay:
R=80+10S
Substituting S = 5 into the equation:
R=80+10(5)=80+50=€130
Therefore, Ruiari's total pay that day was €130.
Step 3
How much was Ruiari paid in tips on that day?
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Answer
To find out how much Ruiari was paid in tips, we need to subtract his fixed rate from his total pay:
Tips=Total Pay−Fixed Rate
So:
Tips=130−80=€50
Ruiari was paid €50 in tips.
Step 4
Explain what this means in the context of Ruiari’s total pay and the customer spend.
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Answer
The point (2, 5, 105) on the graph indicates that when the customer spend is €250 (which corresponds to S = 2.5), Ruiari receives a total pay of €105. This relationship showcases how Ruiari’s total pay comprises his fixed pay and the additional tips earned from the customer spending.
Step 5
Tick (✓) the correct box to show which one corresponds to the graph of Ruiari's total pay. Tick one box only. Justify your answer.
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Answer
The correct equation that corresponds to the graph of Ruiari's total pay is:
R = 80 + 10S.
Justification: This equation matches the fixed pay of €80 and the variable increase of €10 for each additional hundred euro spent.
Step 6
Draw the graph of Cillian’s pay, C, on the axes below, for 0 ≤ S ≤ 5 and S ∈ R.
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To graph Cillian's pay, we will use the equation C = 60 + 20S.
Identify key points:
When S = 0, C = 60 + 20(0) = €60
When S = 1, C = 60 + 20(1) = €80
When S = 2, C = 60 + 20(2) = €100
When S = 3, C = 60 + 20(3) = €120
When S = 4, C = 60 + 20(4) = €140
When S = 5, C = 60 + 20(5) = €160
Plot the points (0, 60), (1, 80), (2, 100), (3, 120), (4, 140), and (5, 160) on the graph.
Connect the points to show a straight line since this is a linear relationship.
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