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Question 15 (i) Write down the co-ordinates of the point A and the point B on the diagram - Junior Cycle Mathematics - Question 15 - 2014

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Question 15

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Question 15 (i) Write down the co-ordinates of the point A and the point B on the diagram. (ii) Use the distance formula to find |AB|. (iii) Write down the distan... show full transcript

Worked Solution & Example Answer:Question 15 (i) Write down the co-ordinates of the point A and the point B on the diagram - Junior Cycle Mathematics - Question 15 - 2014

Step 1

Write down the co-ordinates of the point A and the point B on the diagram.

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Answer

The point A is located on the y-axis where the x-coordinate is 0 and the y-coordinate is 3. Therefore, the co-ordinates of A are:

A = (0, 3)

The point B is on the x-axis where the y-coordinate is 0 and the x-coordinate is 4. Therefore, the co-ordinates of B are:

B = (4, 0)

Step 2

Use the distance formula to find |AB|.

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Answer

The distance formula is given by:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

For points A(0, 3) and B(4, 0), we calculate:

AB=(40)2+(03)2|AB| = \sqrt{(4 - 0)^2 + (0 - 3)^2} =16+9= \sqrt{16 + 9} =25= \sqrt{25} =5= 5

Step 3

Write down the distance from O to A and the distance from O to B.

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Answer

The distance from the origin O(0,0) to A(0,3) is:

OA=3|OA| = 3

The distance from the origin O(0,0) to B(4,0) is:

OB=4|OB| = 4

Step 4

Use the Theorem of Pythagoras to find the length of the hypotenuse of the triangle OBA.

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Answer

Using the Pythagorean theorem:

AB2=OA2+OB2|AB|^2 = |OA|^2 + |OB|^2 AB2=32+42|AB|^2 = 3^2 + 4^2 AB2=9+16|AB|^2 = 9 + 16 AB2=25|AB|^2 = 25

Taking the square root:

AB=25=5|AB| = \sqrt{25} = 5

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