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In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle - Junior Cycle Mathematics - Question 17 - 2014

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Question 17

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In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle. (i) Find the measures of the two acute a... show full transcript

Worked Solution & Example Answer:In the right-angled triangle shown in the diagram, one of the acute angles is four times as large as the other acute angle - Junior Cycle Mathematics - Question 17 - 2014

Step 1

Find the measures of the two acute angles in the triangle.

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Answer

Let the smallest acute angle be denoted as xx. Then, the other acute angle is 4x4x. Since the sum of the angles in a triangle is 180exto180^{ ext{o}} and accounting for the right angle, we can set up the equation:

x+4x+90exto=180extox + 4x + 90^{ ext{o}} = 180^{ ext{o}}

Combining like terms gives:

5x+90exto=180exto5x + 90^{ ext{o}} = 180^{ ext{o}}

Subtracting 90exto90^{ ext{o}} from both sides yields:

5x=90exto5x = 90^{ ext{o}}

Dividing both sides by 5 gives:

x=18extox = 18^{ ext{o}}

Thus, the two acute angles are:

  • The smallest angle: x=18extox = 18^{ ext{o}}
  • The larger angle: 4x=72exto4x = 72^{ ext{o}}

Step 2

Find the slope of the line l that contains the hypotenuse of the triangle.

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Answer

The slope of a line can be calculated as the change in y-values divided by the change in x-values. In this triangle, the hypotenuse creates an angle of 18exto18^{ ext{o}} with the base parallel to the x-axis, where we know:

slope=tan(θ)\text{slope} = \tan(\theta)

Substituting the angle we found, we have:

slope=tan(18o)\text{slope} = \tan(18^{\text{o}})

Using a calculator, we find:

tan(18o)0.325\tan(18^{\text{o}}) \approx 0.325

Therefore, the slope of line l is 0.3250.325 correct to three decimal places.

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