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The diagram below shows part of the frame of a swing on a co-ordinate grid - Junior Cycle Mathematics - Question 6 - 2014

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The diagram below shows part of the frame of a swing on a co-ordinate grid. Each unit on the grid represents one metre. The line segments [AB] and [AC] represent met... show full transcript

Worked Solution & Example Answer:The diagram below shows part of the frame of a swing on a co-ordinate grid - Junior Cycle Mathematics - Question 6 - 2014

Step 1

Write the co-ordinates of the points A, B and C in the spaces provided in the diagram.

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Answer

The coordinates for the points are:

  • A: (0, 5)
  • B: (-4, 0)
  • C: (4, 0)

Step 2

Find the total length of metal bar needed to make this part of the swing.

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Answer

The length of |AB| is calculated as:

|AC| = \\sqrt{(0 - 4)^2 + (5 - 0)^2} = \\sqrt{(-4)^2 + 5^2} = \\sqrt{16 + 25} = \\sqrt{41}$$ The total length of metal bar needed is: $$2 imes |AB| = 2 imes \\sqrt{41} \approx 12.8 ext{ m}$$

Step 3

Find the slope of AB and the slope of AC.

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Answer

The slope of AB is calculated as: Slope of AB=riserun=500(4)=54=1.25\text{Slope of } AB = \frac{\text{rise}}{\text{run}} = \frac{5 - 0}{0 - (-4)} = \frac{5}{4} = 1.25

The slope of AC is: Slope of AC=5004=54=1.25\text{Slope of } AC = \frac{5 - 0}{0 - 4} = \frac{5}{-4} = -1.25

Step 4

Is AB perpendicular to AC? Give a reason for your answer.

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Answer

Answer: No

Reason: The product of slopes is: (54)(54)=1\left(\frac{5}{4} \right) \cdot \left(-\frac{5}{4} \right) = -1 If the product of the slopes is -1, then the lines are perpendicular.

Step 5

Write down the value of tan X, and hence find the size of the angle X.

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Answer

From the triangle OAB: tanX=oppositeadjacent=54tan X = \frac{\text{opposite}}{\text{adjacent}} = \frac{5}{4} To find the angle X: X=tan1(54)51.34|X| = tan^{-1}(\frac{5}{4}) \approx 51.34^{\circ}

Step 6

Find the new height of the swing.

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Answer

The height increase is 20%: Increase=0.2×5=1extm\text{Increase} = 0.2 \times 5 = 1 ext{ m} Therefore, the new height is: New height=5+1=6 m\text{New height} = 5 + 1 = 6 \text{ m} In terms of the adjusted calculation considering |AB| remains the same, the new height calculated yields approximately 6.2 m when corrected. Thus, the final answer is: 6.2extm6.2 ext{ m}

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