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The height of a watercress seedling over six days is shown in the diagram below - Junior Cycle Mathematics - Question 15 - 2012

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The height of a watercress seedling over six days is shown in the diagram below. (a) The plant grows steadily between A and B. It does not grow during two periods. ... show full transcript

Worked Solution & Example Answer:The height of a watercress seedling over six days is shown in the diagram below - Junior Cycle Mathematics - Question 15 - 2012

Step 1

Identify these two periods from the graph.

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Answer

Period 1: B to C Period 2: D to B

Step 2

Find the slope of AB =

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Answer

To find the slope of segment AB, we use the formula:

slope=riserun=12=0.5\text{slope} = \frac{\text{rise}}{\text{run}} = \frac{1}{2} = 0.5

Step 3

Find the slope of CD =

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Answer

To find the slope of segment CD, we use the formula:

slope=riserun=0.51=0.5\text{slope} = \frac{\text{rise}}{\text{run}} = \frac{0.5}{1} = 0.5

Step 4

Do you agree with Janet? Give a reason for your answer.

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Answer

Answer: Yes. Reason: The slopes of the lines are the same.

Step 5

Describe the growth of the seedling over the six days.

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Answer

The seedling grows steadily for two days.

It then stops for a day.

Then it grows for a day.

Finally, it stops growing for two more days.

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