In the diagram below, ABCD is a square and DCE is an equilateral triangle - Junior Cycle Mathematics - Question 9 - 2018
Question 9
In the diagram below, ABCD is a square and DCE is an equilateral triangle.
Some of the angles are marked.
(i) Find the size of the angles W, X, and Y.
Z is the obt... show full transcript
Worked Solution & Example Answer:In the diagram below, ABCD is a square and DCE is an equilateral triangle - Junior Cycle Mathematics - Question 9 - 2018
Step 1
Find the size of the angles W, X, and Y.
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Answer
In square ABCD:
Each angle is 90exto.
Therefore,
Angle W=60exto (from the equilateral triangle DCE).
Angle X=90exto (as it's a right angle in the square).
Angle Y=45exto (since angles in triangle BCA are complementary).
Step 2
Work out the size of the angle Z.
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Answer
Angle Z is obtained by adding the angles W and Y:
Z=W+Y=60exto+45exto=105exto.
Step 3
Use the theorem of Pythagoras to find the value of x.
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Answer
In the square:
Using the theorem of Pythagoras:
x2=52+52x2=25+25=50x=50=7.071
Thus, the length of the diagonal is approximately 7.07 cm (to two decimal places).
Step 4
Construct this diagram in the space below.
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Answer
Draw a square ABCD with each side measuring 5 cm, and an equilateral triangle DCE on top of side DC with each side measuring 5 cm.
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