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In the diagram below, ABCD is a square and DCE is an equilateral triangle - Junior Cycle Mathematics - Question 9 - 2018

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In the diagram below, ABCD is a square and DCE is an equilateral triangle. Some of the angles are marked. (i) Find the size of the angles W, X, and Y. Z is the obt... show full transcript

Worked Solution & Example Answer:In the diagram below, ABCD is a square and DCE is an equilateral triangle - Junior Cycle Mathematics - Question 9 - 2018

Step 1

Find the size of the angles W, X, and Y.

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Answer

In square ABCD:

  • Each angle is 90exto90^ ext{o}. Therefore,
  • Angle W=60extoW = 60^ ext{o} (from the equilateral triangle DCE).
  • Angle X=90extoX = 90^ ext{o} (as it's a right angle in the square).
  • Angle Y=45extoY = 45^ ext{o} (since angles in triangle BCA are complementary).

Step 2

Work out the size of the angle Z.

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Answer

Angle Z is obtained by adding the angles W and Y: Z=W+Y=60exto+45exto=105extoZ = W + Y = 60^ ext{o} + 45^ ext{o} = 105^ ext{o}.

Step 3

Use the theorem of Pythagoras to find the value of x.

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Answer

In the square: Using the theorem of Pythagoras: x2=52+52x^2 = 5^2 + 5^2 x2=25+25=50x^2 = 25 + 25 = 50 x=50=7.071x = \sqrt{50} = 7.071 Thus, the length of the diagonal is approximately 7.077.07 cm (to two decimal places).

Step 4

Construct this diagram in the space below.

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Answer

Draw a square ABCD with each side measuring 5 cm, and an equilateral triangle DCE on top of side DC with each side measuring 5 cm.

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