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Complete the following table for the function $f: x \mapsto -x^2 - 3x - 2$ in the domain $-2 \leq x \leq 4$ - Junior Cycle Mathematics - Question 14 - 2013

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Complete the following table for the function $f: x \mapsto -x^2 - 3x - 2$ in the domain $-2 \leq x \leq 4$. | x | f(x) | (x, f(x)) | |----|------|-----------| | -... show full transcript

Worked Solution & Example Answer:Complete the following table for the function $f: x \mapsto -x^2 - 3x - 2$ in the domain $-2 \leq x \leq 4$ - Junior Cycle Mathematics - Question 14 - 2013

Step 1

Complete the table for the function

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Answer

To complete the table, we need to calculate the values of f(x)f(x) for each xx. The function is given by:

f(x)=x23x2f(x) = -x^2 - 3x - 2

Now, let's find the values:

  • For x=2x = -2: f(2)=(2)23(2)2=4+62=8f(-2) = -(-2)^2 - 3(-2) - 2 = -4 + 6 - 2 = 8

  • For x=1x = -1: f(1)=(1)23(1)2=1+32=0f(-1) = -(-1)^2 - 3(-1) - 2 = -1 + 3 - 2 = 0

  • For x=0x = 0: f(0)=(0)23(0)2=2f(0) = -(0)^2 - 3(0) - 2 = -2

  • For x=1x = 1: f(1)=(1)23(1)2=132=6f(1) = -(1)^2 - 3(1) - 2 = -1 - 3 - 2 = -6

  • For x=2x = 2: f(2)=(2)23(2)2=462=12f(2) = -(2)^2 - 3(2) - 2 = -4 - 6 - 2 = -12

  • For x=3x = 3: f(3)=(3)23(3)2=992=20f(3) = -(3)^2 - 3(3) - 2 = -9 - 9 - 2 = -20

  • For x=4x = 4: f(4)=(4)23(4)2=16122=30f(4) = -(4)^2 - 3(4) - 2 = -16 - 12 - 2 = -30

Thus, the completed table is:

xf(x)(x, f(x))
-28(-2, 8)
-10(-1, 0)
0-2(0, -2)
1-6(1, -6)
2-12(2, -12)
3-20(3, -20)
4-30(4, -30)

Step 2

Draw the graph of the function

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Answer

Using the values from the completed table, we plot the points on a Cartesian coordinate system. The points to plot are:

  • (-2, 8)
  • (-1, 0)
  • (0, -2)
  • (1, -6)
  • (2, -12)
  • (3, -20)
  • (4, -30)

After plotting these points, we can connect them to visualize the graph of the function. The resulting graph will be a downward-opening parabola as the leading coefficient of the x2x^2 term is negative.

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