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The diagram below shows a circle with centre O - Junior Cycle Mathematics - Question 1 - 2018

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The diagram below shows a circle with centre O. The five points A, B, C, D, and E are on the circle. [AB] and [DE] are diameters of the circle, and |∠BOE| = 40°. ... show full transcript

Worked Solution & Example Answer:The diagram below shows a circle with centre O - Junior Cycle Mathematics - Question 1 - 2018

Step 1

Write down the size of the angle X.

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Answer

Since |∠XOD| = 180° for diameter [AD], and |∠BOE| = 40°, we can find |∠X| using the fact that the angles on a straight line sum up to 180°:

X=180°40°=140°X = 180° - 40° = 140°

Thus, X = 40°.

Step 2

Work out the size of the angle Y.

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Answer

Triangle AOD is isosceles, so the base angles are equal. Let |∠AOD| = |∠Y|. Therefore: 180°=40°+2Y180° = 40° + 2Y Solving gives: 140°=2YY=140°2=70°140° = 2Y \\ Y = \frac{140°}{2} = 70°

So, Y = 70°.

Step 3

Work out the size of the angle Z.

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Answer

In cyclic quadrilateral ABCD, opposite angles sum to 180°: Y+Z=180°Z=180°70°=110°Y + Z = 180° \\ Z = 180° - 70° = 110°

Thus, Z = 110°.

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