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Three paths, $[AE]$, $[BE]$ and $[CD]$, have been constructed to provide access to a lake from a road $AC$ as shown in the diagram - Junior Cycle Mathematics - Question 9 - 2014

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Question 9

Three-paths,-$[AE]$,-$[BE]$-and-$[CD]$,-have-been-constructed-to-provide-access-to-a-lake-from-a-road-$AC$-as-shown-in-the-diagram-Junior Cycle Mathematics-Question 9-2014.png

Three paths, $[AE]$, $[BE]$ and $[CD]$, have been constructed to provide access to a lake from a road $AC$ as shown in the diagram. The lengths of the paths from th... show full transcript

Worked Solution & Example Answer:Three paths, $[AE]$, $[BE]$ and $[CD]$, have been constructed to provide access to a lake from a road $AC$ as shown in the diagram - Junior Cycle Mathematics - Question 9 - 2014

Step 1

Explain how these measurements can be used to find |ED|.

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Answer

To find ED|ED|, we can use the property of similar triangles. Triangles ΔAEB\Delta AEB and ΔADC\Delta ADC are similar because they share the angle at AA and both have a right angle. Therefore, their corresponding sides are proportional.

This can be expressed as:

ADAE=CDBE\frac{|AD|}{|AE|} = \frac{|CD|}{|BE|}

Knowing the lengths of AE|AE|, BE|BE|, and CD|CD|, we can substitute these values into the proportion to solve for AD|AD| first, and then find ED|ED|.

Step 2

Find |ED|.

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Answer

We start with the proportionality we established:

AD120=20080\frac{|AD|}{120} = \frac{200}{80}

Cross-multiplying gives:

AD80=120200|AD| \cdot 80 = 120 \cdot 200

Solving for AD|AD|:

AD=12020080=300extm|AD| = \frac{120 \cdot 200}{80} = 300 ext{ m}

Now that we have AD|AD|, we can find ED|ED|:

ED=ADAE=300120=180extm.|ED| = |AD| - |AE| = 300 - 120 = 180 ext{ m}.

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