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In this question, all lengths are in cm and all areas are in cm² - Junior Cycle Mathematics - Question 10 - 2016

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In this question, all lengths are in cm and all areas are in cm². (a) The diagram shows a rectangle with sides of length 7 and y. The value of the area of the recta... show full transcript

Worked Solution & Example Answer:In this question, all lengths are in cm and all areas are in cm² - Junior Cycle Mathematics - Question 10 - 2016

Step 1

The value of the area of the rectangle is equal to the length of its perimeter.

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Answer

For part (a), the area of the rectangle is given by:

A=7yA = 7y

The perimeter of the rectangle can be expressed as:

P=2(7+y)=14+2yP = 2(7 + y) = 14 + 2y

Setting area equal to perimeter:

7y=14+2y7y = 14 + 2y

To solve for y, rearrange the equation:

7y2y=147y - 2y = 14

This simplifies to:

5y=145y = 14

Dividing both sides by 5 gives:

y = rac{14}{5}

Thus, the possible values for y are either 2.82.8 or rac{14}{5}.

Step 2

The value of the area of the rectangle is equal to the length of its perimeter.

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Answer

For part (b), the area of the rectangle is given as:

A=xyA = xy

The perimeter can be expressed as:

P=2(x+y)P = 2(x + y)

Equating area to perimeter, we have:

xy=2(x+y)xy = 2(x + y)

Rearranging this equation leads to:

xy2y=2xxy - 2y = 2x

Factoring out y gives:

y(x2)=2xy(x - 2) = 2x

Now, to solve for y, divide both sides by (x2)(x - 2) (ensuring x>2x > 2):

y = rac{2x}{x - 2}

Thus, we've found y expressed in terms of x.

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