A fair circular spinner consists of three equal sectors - Junior Cycle Mathematics - Question Question 1 - 2012

For this part, we need to consider the outcomes of both the coin toss and the spinner:

• The probability of getting a head is ( \frac{1}{2} ).
• The probability of landing on a red sector is ( \frac{1}{3} ).

The events are independent, so we multiply the probabilities:

$P(Head \text{ and } Red) = P(Head) \times P(Red) = \frac{1}{2} \times \frac{1}{3} = \frac{1}{6}$

Similar to the previous part, we will consider the outcomes of the coin toss and the spinner:

• The probability of getting a tail is also ( \frac{1}{2} ).
• The probability of landing on a blue sector is ( \frac{2}{3} ).

Again, as the events are independent, we multiply the probabilities:

$P(Tail \text{ and } Blue) = P(Tail) \times P(Blue) = \frac{1}{2} \times \frac{2}{3} = \frac{1}{3}$