The marks that 9 students got on a test are:
23 16 13 20 26 15 18 23 30
(a) Write out all 9 marks in order, from the smallest to the biggest - Junior Cycle Mathematics - Question 8 - 2015
Question 8
The marks that 9 students got on a test are:
23 16 13 20 26 15 18 23 30
(a) Write out all 9 marks in order, from the smallest to the biggest.
Answer =
(b) Write... show full transcript
Worked Solution & Example Answer:The marks that 9 students got on a test are:
23 16 13 20 26 15 18 23 30
(a) Write out all 9 marks in order, from the smallest to the biggest - Junior Cycle Mathematics - Question 8 - 2015
Step 1
Write out all 9 marks in order, from the smallest to the biggest.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To arrange the marks from smallest to largest, we list them as follows:
Starting with the smallest: 13,
Then 15,
followed by 16,
then 18,
followed by 20,
then 23 (there are two 23's),
followed by 26,
and finally 30.
Thus, the ordered marks are:
13, 15, 16, 18, 20, 23, 23, 26, 30.
Step 2
Write down the median mark.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the median, we need to determine the middle value in the ordered list of marks. Since there are 9 marks (an odd number), the median is the 5th value in the ordered list. Therefore, the median mark is:
Median mark = 20.
Step 3
Find the range of the marks.
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The range of a set of data is calculated by subtracting the smallest value from the largest value. In this case:
Maximum mark: 30
Minimum mark: 13
Thus, the range is given by:
Range=Maximum−Minimum=30−13=17.
Step 4
Find the new range of the marks.
98%
120 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
When the teacher adds 2 marks to each student’s mark, the maximum and minimum marks also increase by 2.
New Maximum: 30 + 2 = 32
New Minimum: 13 + 2 = 15
Therefore, the new range is:
NewRange=NewMax−NewMin=32−15=17.
Join the Junior Cycle students using SimpleStudy...
