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There are 10 students in a class - Junior Cycle Mathematics - Question 10 - 2015

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There are 10 students in a class. All 10 of them sat a test. The table below shows the mean mark, the median mark, and the range of the marks on the test. 32 was th... show full transcript

Worked Solution & Example Answer:There are 10 students in a class - Junior Cycle Mathematics - Question 10 - 2015

Step 1

Use the range to find the lowest mark got by a student on the test.

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Answer

To find the lowest mark, we can use the formula for range:

extRange=extHighestmarkextLowestmark ext{Range} = ext{Highest mark} - ext{Lowest mark}

Given that the highest mark is 32 and the range is 14, we can calculate:

extLowestmark=extHighestmarkextRange=3214=18. ext{Lowest mark} = ext{Highest mark} - ext{Range} = 32 - 14 = 18.

Thus, the lowest mark got by a student is 18.

Step 2

Find what the mean, the median, and the range would be in this case.

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Answer

If 2 is added to each student's mark, we can update the mean, median, and range as follows:

  1. Mean Calculation:

    • Original Mean: 25
    • Updated Mean: 25 + 2 = 27.
  2. Median Calculation:

    • Original Median: 24
    • Updated Median: 24 + 2 = 26.
  3. Range Calculation:

    • Original Range: 14
    • Adding the same number (2) to all scores does not change the range, so it remains 14.

Updating the table provides:

Results on the test
Mean mark27
Median mark26
Range of the marks14

Step 3

Give an example to show that Bob is not correct.

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Answer

To disprove Bob's statement, we can provide a list of numbers that has a median of 24 but does not contain the number 24:

Example List:

  • 7, 23, 25, 96

To find the median:

  1. Arrange the numbers in ascending order: 7, 23, 25, 96
  2. Since there are four numbers (even number), the median is the average of the two middle values:
ext{Median} = rac{23 + 25}{2} = 24.

This example shows that even when the median is 24, it is not necessary for one of the numbers in the list to be 24.

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