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Seven shapes are shown on the co-ordinate diagram below - Junior Cycle Mathematics - Question 7 - 2018

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Seven shapes are shown on the co-ordinate diagram below. They are labelled A, B, C, D, E, F, and G. (a) Write down the co-ordinates of the vertices (i.e. corners) o... show full transcript

Worked Solution & Example Answer:Seven shapes are shown on the co-ordinate diagram below - Junior Cycle Mathematics - Question 7 - 2018

Step 1

Write down the co-ordinates of the vertices (i.e. corners) of shape B.

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Answer

The coordinates of the vertices of shape B are (2, 4), (5, 4), (5, 1), and (2, 1).

Step 2

Find the area of shape C and the area of shape D.

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Answer

Area of shape C: The shape is a rectangle with base 2 units and height 2 units. Thus, the area is calculated as follows:

AreaC=base×height=2×2=4 units2Area_{C} = base \times height = 2 \times 2 = 4 \text{ units}^2

Area of shape D: The shape is a triangle with base 3 units and height 2 units. Thus, the area is calculated as follows:

AreaD=12×base×height=12×3×2=3 units2Area_{D} = \frac{1}{2} \times base \times height = \frac{1}{2} \times 3 \times 2 = 3 \text{ units}^2

Step 3

Find the length of the perimeter of shape E.

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Answer

The perimeter of shape E can be determined by adding the lengths of its sides. Assuming the sides are measured as 3 units, 5 units, 3 units, and 5 units respectively, then:

PerimeterE=3+5+3+5=16 unitsPerimeter_{E} = 3 + 5 + 3 + 5 = 16 \text{ units}

Step 4

Complete each of the following statements correctly. (i) Shape C has exactly ____ axes of symmetry.

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4 axes of symmetry.

Step 5

Complete each of the following statements correctly. (ii) Shape G is the image of shape ____ under axial symmetry.

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Answer

Shape D.

Step 6

Complete each of the following statements correctly. (iii) Shape A is the image of shape ____ under a translation.

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Answer

Shape B.

Step 7

Find the slope of the hypotenuse of shape B.

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Answer

The slope of the hypotenuse can be determined by examining two points of the line segment. Taking points (2, 4) and (5, 1):

Slope=riserun=1452=33=1Slope = \frac{rise}{run} = \frac{1 - 4}{5 - 2} = \frac{-3}{3} = -1

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