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The diagram below shows the circle k (not to scale) - Junior Cycle Mathematics - Question 12 - 2022

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The diagram below shows the circle k (not to scale). The points A, B, and C lie on the circle. [AB] is a diameter of the circle, and |AC| = 8 cm. The area of the cir... show full transcript

Worked Solution & Example Answer:The diagram below shows the circle k (not to scale) - Junior Cycle Mathematics - Question 12 - 2022

Step 1

Find the Diameter of Circle k

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Answer

The area of the circle is given by the formula: A=πr2A = πr^2. Since the area is 25π cm², we have: 25π=πr225π = πr^2. Dividing both sides by π gives: r2=25r^2 = 25, which results in: r=5extcmr = 5 ext{ cm}. Thus, the diameter, which is twice the radius, is: d=2r=10extcmd = 2r = 10 ext{ cm}.

Step 2

Identify Triangle ABC Properties

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Answer

In triangle ABC, since AB is the diameter, angle ACB is a right angle (90°) according to the inscribed angle theorem. Therefore, we can label the angles:

  • CBA=x|CBA| = x
  • CAB=90°x|CAB| = 90° - x.

Step 3

|AC| = 8 cm

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Answer

According to the given information, |AC| = 8 cm. We can now set up the sine ratio to solve for angle CBA: rac{|AC|}{|AB|} = rac{8}{10} = rac{4}{5}, leading to: ext{sin} |CBA| = rac{4}{5}.

Step 4

Calculate Angle CBA

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Answer

To find angle CBA, take the inverse sine: |CBA| = ext{sin}^{-1}igg( rac{4}{5}igg), which approximately equals 53.13°.

Step 5

Determine Angle CAB

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Answer

Since angle ACB is 90°: CAB=90°CBA=90°53.13°=36.87°.|CAB| = 90° - |CBA| = 90° - 53.13° \\ = 36.87°.

Thus, the angles of triangle ABC are:

  • CBA53.13°|CBA| ≈ 53.13°
  • CAB36.87°|CAB| ≈ 36.87°
  • ACB=90°|ACB| = 90°.

Step 6

Identify the Smallest Angle

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Answer

The smallest angle in triangle ABC is: CAB36.87°.|CAB| ≈ 36.87°.

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