Calculate the size of the angle marked P in the right-angled triangle below - Junior Cycle Mathematics - Question 3
Question 3
Calculate the size of the angle marked P in the right-angled triangle below.
Draw the image of the triangle below under axial symmetry in the line k.
Write down th... show full transcript
Worked Solution & Example Answer:Calculate the size of the angle marked P in the right-angled triangle below - Junior Cycle Mathematics - Question 3
Step 1
Calculate the size of the angle marked P in the right-angled triangle below.
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Answer
To find the size of the angle P in the right-angled triangle, we use the property that the sum of angles in a triangle is 180 degrees. The triangle has one right angle (90 degrees) and the given angle of 22 degrees. Therefore, we can calculate angle P as follows:
P=180ext°−90ext°−22ext°=68ext°
Step 2
Draw the image of the triangle below under axial symmetry in the line k.
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Answer
To draw the triangle under axial symmetry along line k, mirror the right-angled triangle. The left side of the triangle will now appear on the right side of line k, maintaining the same orientation and angle measurements.
Step 3
Write down the length of the side opposite the angle R in the triangle shown.
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Answer
The length of the side opposite the angle R is given as:
Opposite = 12 m.
Step 4
Use the Theorem of Pythagoras to find the length of the hypotenuse of this triangle.
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Answer
To find the hypotenuse (h) using the Theorem of Pythagoras, we use the formula:
h=sqrta2+b2
where:
a = 5 m (one side of the triangle)
b = 12 m (the other side)
Thus,
h=sqrt52+122=sqrt25+144=sqrt169=13m.
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