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Calculate the size of the angle marked P in the right-angled triangle below - Junior Cycle Mathematics - Question 3

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Calculate the size of the angle marked P in the right-angled triangle below. Draw the image of the triangle below under axial symmetry in the line k. Write down th... show full transcript

Worked Solution & Example Answer:Calculate the size of the angle marked P in the right-angled triangle below - Junior Cycle Mathematics - Question 3

Step 1

Calculate the size of the angle marked P in the right-angled triangle below.

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Answer

To find the size of the angle P in the right-angled triangle, we use the property that the sum of angles in a triangle is 180 degrees. The triangle has one right angle (90 degrees) and the given angle of 22 degrees. Therefore, we can calculate angle P as follows:

P=180ext°90ext°22ext°=68ext°P = 180^ ext{°} - 90^ ext{°} - 22^ ext{°} = 68^ ext{°}

Step 2

Draw the image of the triangle below under axial symmetry in the line k.

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Answer

To draw the triangle under axial symmetry along line k, mirror the right-angled triangle. The left side of the triangle will now appear on the right side of line k, maintaining the same orientation and angle measurements.

Step 3

Write down the length of the side opposite the angle R in the triangle shown.

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Answer

The length of the side opposite the angle R is given as:

Opposite = 12 m.

Step 4

Use the Theorem of Pythagoras to find the length of the hypotenuse of this triangle.

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Answer

To find the hypotenuse (h) using the Theorem of Pythagoras, we use the formula:

h=sqrta2+b2h = \\sqrt{a^2 + b^2} where:

  • a = 5 m (one side of the triangle)
  • b = 12 m (the other side)

Thus,

h=sqrt52+122=sqrt25+144=sqrt169=13mh = \\sqrt{5^2 + 12^2} = \\sqrt{25 + 144} = \\sqrt{169} = 13 m.

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