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Use trigonometry to work out the value of $x$ in the diagram below - Junior Cycle Mathematics - Question 13 - 2019

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Use trigonometry to work out the value of $x$ in the diagram below. Give your answer correct to two decimal places. The triangle has one angle measuring $20^{ ext{... show full transcript

Worked Solution & Example Answer:Use trigonometry to work out the value of $x$ in the diagram below - Junior Cycle Mathematics - Question 13 - 2019

Step 1

Use trigonometry to work out the value of x in the diagram below.

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Answer

To find the value of xx, we can use the tangent function. The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side. Here, we have:

an(20ext°)=6x an(20^{ ext{°}}) = \frac{6}{x}

Rearranging the equation gives:

x=6tan(20ext°)x = \frac{6}{\tan(20^{ ext{°}})}

Using a calculator, we find:

x60.364016.48x \approx \frac{6}{0.3640} \approx 16.48

Therefore, the value of xx is approximately 16.4816.48.

Step 2

Use this to prove that: cos Y + sin Y > 1

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Answer

In the triangle with sides aa, bb, and cc, we are given that:

a+b>ca + b > c

We can relate this to the trigonometric functions:

By definition, we have:

cosY=bc and sinY=ac\cos Y = \frac{b}{c} \quad \text{ and } \quad \sin Y = \frac{a}{c}

Now, substituting these values into the inequality:

cosY+sinY=bc+ac=a+bc\cos Y + \sin Y = \frac{b}{c} + \frac{a}{c} = \frac{a + b}{c}

Since a+b>ca + b > c, we divide both sides by cc (noting that c>0c > 0):

a+bc>1\frac{a + b}{c} > 1

Thus, we arrive at:

cosY+sinY>1\cos Y + \sin Y > 1

This proves the statement.

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