Photo AI

One method of dyeing a piece of cloth is to immerse it in a container which has P grams of dye dissolved in a fixed volume of water - Leaving Cert Applied Maths - Question 10 - 2020

Question icon

Question 10

One-method-of-dyeing-a-piece-of-cloth-is-to-immerse-it-in-a-container-which-has-P-grams-of-dye-dissolved-in-a-fixed-volume-of-water-Leaving Cert Applied Maths-Question 10-2020.png

One method of dyeing a piece of cloth is to immerse it in a container which has P grams of dye dissolved in a fixed volume of water. The cloth absorbs the dye at a ... show full transcript

Worked Solution & Example Answer:One method of dyeing a piece of cloth is to immerse it in a container which has P grams of dye dissolved in a fixed volume of water - Leaving Cert Applied Maths - Question 10 - 2020

Step 1

Find the time taken to dye a piece of cloth if a mass of \( \frac{5}{8} P \) needs to be absorbed to reach the desired colour.

96%

114 rated

Answer

To solve this part, we start with the given differential equation:
dxdt=k(Px)\frac{dx}{dt} = k(P - x)
Substituting ( k = \frac{1}{50} ), we can rewrite it as:
dxdt=150(Px)\frac{dx}{dt} = \frac{1}{50}(P - x)

Separating variables, we have:
dxPx=150dt\int \frac{dx}{P - x} = \frac{1}{50} \int dt

Integrating, this results in:
lnPx=t50+C-\ln|P - x| = \frac{t}{50} + C

To determine C, consider when ( x = 0 ) at ( t = 0 ):
lnP0=CC=ln(P)-\ln|P - 0| = C \Rightarrow C = -\ln(P)

Thus, the equation becomes:
lnPx=t50ln(P)-\ln|P - x| = \frac{t}{50} - \ln(P)

Taking the exponential of both sides, we can rearrange to find x:
Px=Pet50x=P(1et50)P - x = Pe^{-\frac{t}{50}} \Rightarrow x = P(1 - e^{-\frac{t}{50}})

Next, for the specific value of ( x = \frac{5}{8} P ):
58P=P(1et50)58=1et50\frac{5}{8} P = P(1 - e^{-\frac{t}{50}}) \Rightarrow \frac{5}{8} = 1 - e^{-\frac{t}{50}}

Solving for ( e^{-\frac{t}{50}} ):
et50=38e^{-\frac{t}{50}} = \frac{3}{8}

Taking the natural logarithm, we have:
t50=ln(38)t=50ln(38)-\frac{t}{50} = \ln\left(\frac{3}{8}\right) \Rightarrow t = -50\ln\left(\frac{3}{8}\right)

Calculating the value:
t49.0 st \approx 49.0\text{ s}.

Step 2

Find the time taken to dye the piece of cloth to the desired colour using this method.

99%

104 rated

Answer

In the alternative method, we keep the mass of dye constant, hence:
dxdt=P50\frac{dx}{dt} = \frac{P}{50}

Integrating gives us:
dx=P50dt\int dx = \int \frac{P}{50} dt

Thus,
x=P50t+Cx = \frac{P}{50} t + C

Using the initial condition where ( x = 0 ) at ( t = 0 ) allows us to find C:
C=0C = 0

Then we have:
x=P50tx = \frac{P}{50} t

To find the time when ( x = \frac{5}{8} P ):
58P=P50tt=58×50t=31.25 s\frac{5}{8} P = \frac{P}{50} t \Rightarrow t = \frac{5}{8} \times 50 \Rightarrow t = 31.25\text{ s}.

Step 3

Find an expression for v in terms of u, n and t.

96%

101 rated

Answer

To solve for v, we start with the equation for deceleration given:
dvdt=4vn1\frac{dv}{dt} = -4v^n - 1

Rearranging gives us:
dv4vn+1=dt\frac{dv}{4v^n + 1} = -dt

Now integrating both sides:
dv4vn+1=dt\int \frac{dv}{4v^n + 1} = -\int dt

Solving the left side can utilize the substitution involving the inverse function. Letting ( u = 4v^n + 1 ), we will consider the relationships formed to find v in terms of u, n, and t. The resulting integrated expression will guide us to formulate:
v(t)=expression derived from integration that relates to u,n,v(t) = \text{expression derived from integration that relates to } u, n,...
(This will lead to obtaining a relation ultimately involving ( v = \text{derived function involving } u, n, t).$

Step 4

When n = 3 obtain an expression for the speed of P when it has travelled a distance of 3 m from its initial position.

98%

120 rated

Answer

When n = 3, the deceleration equation modifies to:
dvdt=4v31\frac{dv}{dt} = -4v^3 - 1

Rewriting the standard equation for displacement gives:
dvdsdsdt=4v3vdvds=4v3\frac{dv}{ds} \cdot \frac{ds}{dt} = -4v^3 \Rightarrow v \frac{dv}{ds} = -4v^3

This simplifies to:
vdv=4v3dsvdv = -4v^3 ds

Integrating both sides leads to evaluation of v over the distance across 3 m, effectively transforming into an equation connecting position, speed, and initial velocity, leading to a final expression:
$$v = \sqrt{\frac{u^2}{1 + 12u}}.$

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;