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Question 9
9. (a) A right circular solid cylinder floats at rest in water with its axis vertical. The radius of the cylinder is 6 cm and its height is 20 cm. 75% of the cylin... show full transcript
Step 1
Answer
We start by calculating the volume of the submerged part of the cylinder.
The height submerged is:
The volume of the submerged part of the cylinder is given by:
V = ext{Area} imes h = rac{22}{7} imes (0.06)^2 imes 0.15
Calculating this gives:
V = rac{22}{7} imes 0.0036 imes 0.15 = 0.00076 ext{ m}^3
The weight of the water displaced (which is equal to the weight of the cylinder in equilibrium) is:
This evaluates to approximately:
Step 2
Answer
For the sphere held in equilibrium, the buoyant force, tension in the string (T), and the weight of the sphere (W) are related by:
The weight of the sphere is calculated as:
Where the volume of the sphere is:
V = rac{4}{3} imes rac{22}{7} imes (0.07^3)
Calculating W gives:
After simplifying, we find that:
Now we can find T by substituting into the previous equation:
Since the relative density of the liquid is given, we find that the buoyant force can also be calculated using the formula for buoyant force.
Finally calculating T gives:
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