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Question 8
Define (i) acid, (ii) conjugate acid, according to the Brønsted-Lowry theory. In acting as an acid-base indicator methyl orange behaves like a weak acid. Letting H... show full transcript
Step 1
Answer
A Brønsted-Lowry acid is defined as a proton (H⁺) donor. This means that an acid is any species that can donate a proton to another species during a chemical reaction.
A conjugate acid is the species formed when a Brønsted-Lowry base accepts a proton. When the base gains a proton, it becomes the conjugate acid of that base.
Step 2
Answer
A strong acid completely dissociates in aqueous solution, meaning that it donates all its available protons to the solution, resulting in a high concentration of H⁺ ions. An example of a strong acid is hydrochloric acid (HCl). In contrast, a weak acid only partially dissociates in solution, leading to a lower concentration of H⁺ ions. A typical example of a weak acid is acetic acid. The key difference lies in their degree of ionization in water.
Step 3
Step 4
Answer
(i) When a few drops of methyl orange are added to a 0.1 M solution of HCl, the solution will appear red. This occurs because HCl is a strong acid, and the resulting high concentration of H⁺ ions favors the undissociated form (HX) of the indicator, which is red.
(ii) When the same number of drops is added to a 0.1 M solution of NaOH, the solution will appear yellow. NaOH is a strong base, and it causes the methyl orange to dissociate into its conjugate base (X⁻), which gives a yellow coloration.
Step 5
Answer
(i) To calculate the pH of a 0.1 M NaOH solution, we first find the concentration of OH⁻ ions. For a strong base like NaOH, this is equal to its concentration: [OH⁻] = 0.1 M.
Using the formula:
Calculating pH from pOH:
(ii) For the 0.004 M solution of methyl orange with a Ka of 3.5 x 10⁻⁴, we can utilize the equation:
Where the concentration of H⁺ in equilibrium can be found using the relation:
K_a = rac{[H^+][X^-]}{[HX]}
For a weak acid, we can assume that [H⁺] is approximately equal to [X⁻]. Thus,
K_a = rac{x^2}{0.004 - x} ext{ (where x is negligible)}
We find
ext{Solving gives,} ext{pH} = 2.9.
Step 6
Answer
The pH curve for the titration of HCl with NaOH is characterized by a steep slope at the equivalence point.
The x-axis represents the volume of NaOH added, while the y-axis represents the pH.
Label the pH scale from 0 to 14 and indicate the expected shape of the curve starting from low pH, rising steeply around the equivalence point, and leveling out as it approaches neutral pH.
Mark the initial volumes: 25 cm³ of HCl and the volume at which the equivalence point occurs, which should correspond to the neutralization of the acid and base, around 50 cm³ of NaOH added.
Explain that the curve shows a rapid pH change in the range below 7 during the addition of NaOH until it approaches 7, where most indicators will change color due to the steep slope of the curve.
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