Calculate the pH of 0.15 M sulfuric acid (H₂SO₄) correct to one decimal place. - Leaving Cert Chemistry - Question e - 2018
Question e
Calculate the pH of 0.15 M sulfuric acid (H₂SO₄) correct to one decimal place.
Worked Solution & Example Answer:Calculate the pH of 0.15 M sulfuric acid (H₂SO₄) correct to one decimal place. - Leaving Cert Chemistry - Question e - 2018
Step 1
Step 1: Determine the concentration of
[H⁺] ions
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
Sulfuric acid (H₂SO₄) is a strong acid that dissociates completely in water. In this case, we need to consider that each molecule of H₂SO₄ produces two H⁺ ions. Therefore, the concentration of H⁺ ions can be calculated as follows:
[H+]=2imes[H2SO4]=2imes0.15extM=0.30extM
Step 2
Step 2: Calculate the pH
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The pH is calculated using the formula:
extpH=−extlog10[H+]
Substituting the concentration of H⁺ ions:
extpH=−extlog10(0.30)
Using a calculator, we find:
extpHextext≈0.5
Join the Leaving Cert students using SimpleStudy...
