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In 1884, the Swedish chemist, pictured on the right, proposed a new theory of acids and bases - Leaving Cert Chemistry - Question 7 - 2006

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In 1884, the Swedish chemist, pictured on the right, proposed a new theory of acids and bases. He defined an acid as a substance which produces hydrogen ions (H+) by... show full transcript

Worked Solution & Example Answer:In 1884, the Swedish chemist, pictured on the right, proposed a new theory of acids and bases - Leaving Cert Chemistry - Question 7 - 2006

Step 1

Identify the Swedish chemist.

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Answer

The Swedish chemist referred to in the question is Svante Arrhenius, known for his theory of electrolytic dissociation.

Step 2

Define base according to the theory proposed by this chemist.

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Answer

According to Arrhenius's theory, a base is defined as a substance that produces hydroxide ions (OH−) when dissolved in water.

Step 3

Give one example of a common household acid and one example of a common household base.

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Answer

A common household acid is vinegar (acetic acid), and a common household base is baking soda (sodium bicarbonate).

Step 4

What do you understand by the term neutralisation? Give one everyday example.

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Answer

Neutralisation is the chemical reaction between an acid and a base that produces a salt and water. An everyday example of neutralisation is mixing vinegar with baking soda, resulting in a fizzing reaction that produces carbon dioxide gas.

Step 5

Define pH.

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Answer

pH is defined as the negative logarithm to the base ten of the hydrogen ion concentration in a solution, expressed as:

o = - ext{log}_{10} [H^+]

Step 6

What is the concentration of the solution in moles per litre?

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Answer

To find the concentration in moles per litre, first, calculate the molar mass of NaOH, which is approximately 40 g/mol. Therefore, the concentration in moles per litre is calculated as follows:

ext{Concentration} = rac{	ext{mass (g)}}{	ext{molar mass (g/mol)} 	imes 	ext{volume (L)}} = rac{4.0 	ext{ g}}{40 	ext{ g/mol}} = 0.1 	ext{ mol/L}

Step 7

Calculate the pH of the solution.

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Answer

To calculate the pH of a 0.1 mol/L NaOH solution, first, find the pOH:

pOH = - ext{log}{10} [OH^-] = - ext{log}{10} [0.1] = 1.

Next, use the relationship between pH and pOH:

pH + pOH = 14

Thus, pH = 14 - 1 = 13.

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