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How many (i) protons, (ii) neutrons are there in the selenium atom $^{82}_{34}Se$? - Leaving Cert Chemistry - Question (a) - 2001

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Question (a)

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How many (i) protons, (ii) neutrons are there in the selenium atom $^{82}_{34}Se$?

Worked Solution & Example Answer:How many (i) protons, (ii) neutrons are there in the selenium atom $^{82}_{34}Se$? - Leaving Cert Chemistry - Question (a) - 2001

Step 1

(i) protons

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Answer

The atomic number of selenium (Se) is 34. Therefore, there are 34 protons in the selenium atom 3482Se^{82}_{34}Se.

Step 2

(ii) neutrons

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Answer

To find the number of neutrons, we use the formula:

extNeutrons=extMassNumber−extAtomicNumber ext{Neutrons} = ext{Mass Number} - ext{Atomic Number}

In this case, the mass number of selenium in 3482Se^{82}_{34}Se is 82. Therefore:

extNeutrons=82−34=48 ext{Neutrons} = 82 - 34 = 48

Thus, there are 48 neutrons in the selenium atom 3482Se^{82}_{34}Se.

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