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‘Methanal (HCHO), ethanoic acid (CH₃COOH) and glucose (C₆H₁₂O₆) all have the same empirical formula.’ Is the statement above true or false? Explain. - Leaving Cert Chemistry - Question g - 2021

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‘Methanal-(HCHO),-ethanoic-acid-(CH₃COOH)-and-glucose-(C₆H₁₂O₆)-all-have-the-same-empirical-formula.’---Is-the-statement-above-true-or-false?-Explain.-Leaving Cert Chemistry-Question g-2021.png

‘Methanal (HCHO), ethanoic acid (CH₃COOH) and glucose (C₆H₁₂O₆) all have the same empirical formula.’ Is the statement above true or false? Explain.

Worked Solution & Example Answer:‘Methanal (HCHO), ethanoic acid (CH₃COOH) and glucose (C₆H₁₂O₆) all have the same empirical formula.’ Is the statement above true or false? Explain. - Leaving Cert Chemistry - Question g - 2021

Step 1

Determine the Empirical Formula for Each Compound

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Answer

  1. Methanal (HCHO):

    • The molecular formula is C₁H₁O₁.
    • The empirical formula is also CH₂O since we can divide the subscripts by 1.

  2. Ethanoic Acid (CH₃COOH):

    • The molecular formula is C₂H₄O₂.
    • The empirical formula is also CH₂O by dividing the subscripts by 2.

  3. Glucose (C₆H₁₂O₆):

    • The molecular formula is C₆H₁₂O₆.
    • The empirical formula is CH₂O since all subscripts can be divided by 6.

Step 2

Compare the Empirical Formulas

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Answer

The empirical formulas for methanal (CH₂O), ethanoic acid (CH₂O), and glucose (CH₂O) are all the same.

Step 3

Conclusion

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Answer

Thus, the statement is true as all three compounds share the same empirical formula, CH₂O.

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