Photo AI

Refinery gas, naphtha, kerosene and gas oil are products of the fractionation of crude oil - Leaving Cert Chemistry - Question 6 - 2018

Question icon

Question 6

Refinery-gas,-naphtha,-kerosene-and-gas-oil-are-products-of-the-fractionation-of-crude-oil-Leaving Cert Chemistry-Question 6-2018.png

Refinery gas, naphtha, kerosene and gas oil are products of the fractionation of crude oil. (a) Explain the underlined term. (b) Name the two major components of l... show full transcript

Worked Solution & Example Answer:Refinery gas, naphtha, kerosene and gas oil are products of the fractionation of crude oil - Leaving Cert Chemistry - Question 6 - 2018

Step 1

Explain the underlined term.

96%

114 rated

Answer

The underlined term refers to the separation or splitting of crude oil into its various components based on differences in molecular size and boiling points. This process is achieved through distillation, where the crude oil is heated, and its components are separated as they vaporize at different temperatures.

Step 2

Name the two major components of liquefied petroleum gas (LPG), a fuel obtained from refinery gas.

99%

104 rated

Answer

The two major components of liquefied petroleum gas (LPG) are propane and butane.

Step 3

Why is methanethiol (CH₃SH), a mercaptan, added to natural gas and to LPG?

96%

101 rated

Answer

Methanethiol (CH₃SH) is added to natural gas and LPG as an odorant. Since both gases are colorless and odorless, the addition of methanethiol provides a distinct smell, which helps in detecting leaks and ensuring safety.

Step 4

Calculate the heat of combustion of methanethiol according to the equation.

98%

120 rated

Answer

To calculate the heat of combustion, we use the heats of formation:

extΔHextcombustion=extΣΔHextproductsextΣΔHextreactants. ext{ΔH}_{ ext{combustion}} = ext{Σ ΔH}_{ ext{products}} - ext{Σ ΔH}_{ ext{reactants}}.

Based on the equation:

extCH3extSH+3extO2(g)extCO2(g)+2extH2extO(l)+extSO2(g) ext{CH}_3 ext{SH} + 3 ext{O}_2 (g) → ext{CO}_2 (g) + 2 ext{H}_2 ext{O} (l) + ext{SO}_2 (g)

We find:

extΔHextcombustion=[extΔH(extCO2)+2imesextΔH(extH2extO)+extΔH(extSO2)][extΔH(extCH3extSH)+3imesextΔH(extO2)] ext{ΔH}_{ ext{combustion}} = [ ext{ΔH}( ext{CO}_2) + 2 imes ext{ΔH}( ext{H}_2 ext{O}) + ext{ΔH}( ext{SO}_2)] - [ ext{ΔH}( ext{CH}_3 ext{SH}) + 3 imes ext{ΔH}( ext{O}_2)]

Substituting the given values:

Thus,

extΔHextcombustion=1239.1extkJmol1. ext{ΔH}_{ ext{combustion}} = -1239.1 ext{ kJ mol}^{-1}.

Step 5

Give the IUPAC names for the four hydrocarbon products shown above.

97%

117 rated

Answer

The IUPAC names for the hydrocarbon products are:

  1. 2,2,4-trimethylpentane
  2. butane
  3. 1-butene
  4. ethylbenzene

Step 6

Identify the processes B and C.

97%

121 rated

Answer

Process B is catalytic cracking, and Process C is dehydrocyclization.

Step 7

Where are processes A, B and C carried out?

96%

114 rated

Answer

Processes A, B, and C are typically carried out in an oil refinery, specifically in the distillation and conversion units.

Step 8

How would you expect the boiling points of petrol and diesel to compare?

99%

104 rated

Answer

Diesel generally has a higher boiling point compared to petrol. This is due to the fact that petrol comprises hydrocarbons with fewer carbon atoms (5 to 10) while diesel has longer-chain hydrocarbons (14 to 19), leading to stronger intermolecular forces and thus higher boiling points for diesel.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;