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The following hydrocarbons can all be used as fuels - Leaving Cert Chemistry - Question 8 - 2002

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The following hydrocarbons can all be used as fuels. methane (CH₄) butane (C₄H₁₀) 2,2,4-trimethylpentane (C₈H₁₈) a) Butane is a major component of LPG. What do t... show full transcript

Worked Solution & Example Answer:The following hydrocarbons can all be used as fuels - Leaving Cert Chemistry - Question 8 - 2002

Step 1

a) What do the letters LPG stand for?

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Answer

LPG stands for Liquefied Petroleum Gas.

Step 2

a) Draw two structural isomers of butane.

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Answer

The two structural isomers of butane (C₄H₁₀) are:

  1. n-butane:
    CH₃−CH₂−CH₂−CH₃
  2. Isobutane (2-methylpropane):
    CH₃−CH(CH₃)−CH₃

Step 3

b) Why are mercaptans often added to natural gas?

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Answer

Mercaptans are added to natural gas primarily to give it an odor, allowing for detection of gas leaks. This is crucial for safety as natural gas is odorless and can pose explosion risks.

Step 4

b) Apart from leaking gas pipes, name a major source from which methane is released to the atmosphere.

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Answer

A major source of methane released to the atmosphere is agricultural activities, particularly from livestock digestion (enteric fermentation) and manure management.

Step 5

c) What structural feature of 2,2,4-trimethylpentane results in it having a high octane rating?

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Answer

The presence of branching in the structure of 2,2,4-trimethylpentane contributes to its high octane rating. Branched hydrocarbons tend to burn more smoothly and are less likely to knock.

Step 6

c) Give one other structural feature which increases the octane number of a hydrocarbon.

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Answer

The presence of methyl branches or a short carbon chain structure also increases the octane number of hydrocarbons.

Step 7

d) Define heat of combustion of a compound.

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Answer

The heat of combustion of a compound is the amount of energy released when one mole of the substance undergoes complete combustion with oxygen, forming carbon dioxide and water.

Step 8

e) Calculate the heat of combustion of butane.

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Answer

To calculate the heat of combustion, use the formula:

extΔHcomb=extΣΔHf(products)extΣΔHf(reactants) ext{ΔH}_{comb} = ext{ΣΔH_f(products)} - ext{ΣΔH_f(reactants)}

From the balanced equation:

2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

The heats of formation are:
ΔH_f(C₄H₁₀) = -125 kJ/mol,
ΔH_f(CO₂) = -394 kJ/mol,
ΔH_f(H₂O) = -286 kJ/mol.

Calculating:

  • For products:
    8(-394) + 10(-286) = -3152 - 2860 = -6012 kJ/mol

  • For reactants:
    2(-125) = -250 kJ/mol

Thus,

extΔHcomb=6012(250)=5762kJ/mol ext{ΔH}_{comb} = -6012 - (-250) = -5762 kJ/mol

The heat of combustion of butane is -5762 kJ/mol.

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