Name the oil refining process shown in the diagram - Leaving Cert Chemistry - Question 6 - 2016
Question 6
Name the oil refining process shown in the diagram.
Naphtha is a mixture of hydrocarbons of similar relative molecular masses.
Identify the physical property that is... show full transcript
Worked Solution & Example Answer:Name the oil refining process shown in the diagram - Leaving Cert Chemistry - Question 6 - 2016
Step 1
Name the oil refining process shown in the diagram.
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Answer
The oil refining process shown in the diagram is called fractionation or fractional distillation.
Step 2
Identify the physical property that is the basis for these hydrocarbons being isolated as naphtha in this process.
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Answer
The physical property that allows hydrocarbons to be isolated as naphtha in this process is the boiling (condensing) point (temperature).
Step 3
Give a major use for kerosene.
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Answer
A major use for kerosene is as aviation (airplane, jet) fuel.
Step 4
Give a major use for residue.
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A major use for residue is in roofing, road making, or waterproofing.
Step 5
Name the oil refining process that converts octane into 2,2,4-trimethylpentane.
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Answer
The oil refining process that converts octane into 2,2,4-trimethylpentane is called isomerisation.
Step 6
Name the oil refining process that converts octane into ethylene according to the following balanced equation.
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The oil refining process that converts octane into ethylene is called dehydrocyclisation/reforming.
Step 7
Explain why these conversions are desirable.
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These conversions are desirable because they improve octane rating (number), which reduces the tendency of fuels to cause knocking. This is achieved by producing shorter chained hydrocarbons, which are more branched and therefore more efficient.
Step 8
Calculate the heat of reaction for the conversion of octane to ethylene above.
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To calculate the heat of reaction, we apply Hess's Law. We can calculate it using the equation:
Deduce the molecular formula of the third molecule formed.
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Answer
Since the two known hydrocarbons are octane (C₈H₁₈) and propane (C₃H₈), we can find the molecular formula of the third molecule (C₁₈H₃₈ - C₈H₁₈ - C₃H₈) which results in:
C18H38−C8H18−C3H8=C7H12
Thus, the molecular formula of the third molecule is C₇H₁₂.
Step 10
Draw the molecular structure of (i) octane.
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The molecular structure of octane (C₈H₁₈) is:
H H H H H H H
| | | | | | |
H - C - C - C - C - C - C - C - C - H
| | | | | | |
H H H H H H H
Octane has a straight-chain structure.
Step 11
Draw the molecular structure of (ii) 2,2,4-trimethylpentane.
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The molecular structure of 2,2,4-trimethylpentane (C₈H₁₈) is:
H H H
| | |
H - C - C - C - H
| | |
H C - C - H
| |
H H
|
H
It has a branched structure.
Step 12
Draw the molecular structure of (iii) ethylbenzene.
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The molecular structure of ethylbenzene (C₈H₁₀) is:
H H
| |
H - C - C - H
| |
C - C
| |
H H
Ethylbenzene consists of a benzene ring with an ethyl group.
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