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From July 2008 changes will apply to the way in which taxes are levied on new cars bought in Ireland - Leaving Cert Chemistry - Question b - 2008

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From July 2008 changes will apply to the way in which taxes are levied on new cars bought in Ireland. Vehicles that, in controlled tests, have higher levels of carbo... show full transcript

Worked Solution & Example Answer:From July 2008 changes will apply to the way in which taxes are levied on new cars bought in Ireland - Leaving Cert Chemistry - Question b - 2008

Step 1

Calculate the mass of CO₂

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Answer

To find the mass of CO₂ produced, we first calculate the total weight of CO₂ produced per day:

Mass of CO₂ = Emission per km x Distance

This gives us:

extMassofCO2=143extg/kmimes8extkm=1144extg ext{Mass of CO₂} = 143 ext{ g/km} imes 8 ext{ km} = 1144 ext{ g}

Step 2

Calculate the number of moles of CO₂

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Answer

Using the molar mass of CO₂ (44 g/mol), we calculate the number of moles as follows:

extNumberofmoles=Mass of CO₂Molar mass of CO₂ ext{Number of moles} = \frac{\text{Mass of CO₂}}{\text{Molar mass of CO₂}}

=1144extg44extg/mol=26extmol= \frac{1144 ext{ g}}{44 ext{ g/mol}} = 26 ext{ mol}

Step 3

Calculate the volume of CO₂ at room temperature and pressure

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Answer

At room temperature and pressure, one mole of gas occupies approximately 24 liters. Therefore, the total volume of CO₂ produced is:

Volume of CO₂=Number of moles×24extL/mol\text{Volume of CO₂} = \text{Number of moles} \times 24 ext{ L/mol}

Calculating this gives:

Volume of CO₂=26extmol×24extL/mol=624extL\text{Volume of CO₂} = 26 ext{ mol} \times 24 ext{ L/mol} = 624 ext{ L}

Step 4

Calculate additional CO₂ from the large SUV

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Answer

For the large SUV with an emission of 264 g CO₂/km, we first calculate the total emission:

Mass of CO₂ (SUV)=264extg/km×8extkm=2112extg\text{Mass of CO₂ (SUV)} = 264 ext{ g/km} \times 8 ext{ km} = 2112 ext{ g}

The difference in mass produced by using the SUV:

Difference in mass=2112extg1144extg=968extg\text{Difference in mass} = 2112 ext{ g} - 1144 ext{ g} = 968 ext{ g}

Next, to find how many liters of this difference would be released:

Additional volume=968extg44extg/mol×24extL/mol=528extL\text{Additional volume} = \frac{968 ext{ g}}{44 ext{ g/mol}} \times 24 ext{ L/mol} = 528 ext{ L}

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