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Study the reaction scheme below and answer the questions that follow - Leaving Cert Chemistry - Question 8 - 2015

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Study the reaction scheme below and answer the questions that follow. C₃H₈ A x CH₃CHOHCH₃ B Y CH₃COCH₃ ... show full transcript

Worked Solution & Example Answer:Study the reaction scheme below and answer the questions that follow - Leaving Cert Chemistry - Question 8 - 2015

Step 1

Give the IUPAC names for A, B and C.

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Answer

The IUPAC names for the given compounds are as follows:

  • A: Propene (or Prop-1-ene)
  • B: 2-propanol (or Propan-2-ol)
  • C: Propanone (or Propan-2-one)

Step 2

Name the addition polymer formed from compound A.

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Answer

The addition polymer formed from compound A (Propene) is poly(propene) or polypropylene.

Step 3

Identify the bonds broken and the bonds formed in conversion Y.

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Answer

In conversion Y:

  • Bonds broken: 1 C-O bond (pi bond of carbonyl) and 1 O-H bond
  • Bonds formed: 1 C-C bond and 1 C-O bond

Step 4

An isomer of compound B can be synthesised from an aldehyde. Name the isomer of compound B and the aldehyde and draw their full structural formulae.

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Answer

The isomer of compound B is 1-propanol (or propan-1-ol), which can be synthesized from the aldehyde propanal (or propanaldehyde).

Structural formulae:

  • Isomer (1-propanol):

    CH₃-CH₂-CH₂-OH

  • Aldehyde (propanal):

    CH₃-CH₂-CHO

Step 5

How can the aldehyde be converted to the isomer of compound B?

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Answer

The conversion of propanal (the aldehyde) to 1-propanol can be achieved through a reduction reaction. This can be performed using reagents such as hydrogen (H₂) with a catalyst like nickel (Ni) or using lithium aluminium hydride (LiAlH₄).

Step 6

The boiling points of compounds A, B and C are -48, -56 and 82 °C, but not necessarily in that order. For each compound, identify its boiling point, justifying your answer in terms of intermolecular forces.

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Answer

Based on the nature of the compounds:

  • A (Propene, boiling point -48 °C): Propene experiences weaker van der Waals forces due to its non-polar characteristics.
  • B (2-propanol, boiling point -56 °C): 2-propanol is capable of hydrogen bonding due to its hydroxyl (-OH) group, leading to a comparatively lower boiling point than propanone.
  • C (Propanone, boiling point 82 °C): Propanone (acetone) also has dipole-dipole interactions between molecules, along with some van der Waals forces, leading to a higher boiling point than the others.

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