Define reduction in terms of (i) electron transfer, (ii) change in oxidation number - Leaving Cert Chemistry - Question b - 2016
Question b
Define reduction in terms of (i) electron transfer, (ii) change in oxidation number.
$$ClO^- + SO_2^{2-} + OH^- \rightarrow Cl^- + SO_4^{2-} + H^+$$
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Worked Solution & Example Answer:Define reduction in terms of (i) electron transfer, (ii) change in oxidation number - Leaving Cert Chemistry - Question b - 2016
Step 1
(i) electron transfer
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Answer
Reduction is defined as the gain of electrons. In a redox reaction, the species undergoing reduction receives electrons from the oxidizing agent.
Step 2
(ii) change in oxidation number
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Answer
Reduction can also be defined as a decrease in oxidation number. When a substance is reduced, its oxidation state decreases, indicating a gain of electrons.
Step 3
(iii) the reducing reagent
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Answer
In the equation ClO−+SO22−+OH−→Cl−+SO42−+H+, the reducing agent is SO22−. This species donates electrons to the ClO−, leading to the reduction of chlorine.
Step 4
(iv) the oxidising reagent
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In the same equation, the oxidizing agent is ClO−. It accepts electrons from the SO22−, thus causing the oxidation of sulfur.
Step 5
Using oxidation numbers, or otherwise, balance either equation
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Answer
To balance the equation 4ClO−+SO22−+4OH−→4Cl−+2SO42−+2H+, we first determine the oxidation states:
Chlorine in ClO− is +1, and in Cl− is -1.
Sulfur in SO22− is +4, and in SO42− is +6.
The balanced equation maintains conservation of mass and charge, ensuring that the number of each type of atom and the charges are equal on both sides.
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