To investigate the effect of concentration on a reaction rate, a student measured 100 cm³ of a 0.10 M solution of sodium thiosulfate into a conical flask, added 10 cm³ of 1.0 M hydrochloric acid, and then placed the flask on top of a cross on a sheet of white paper as shown in the diagram - Leaving Cert Chemistry - Question 3 - 2002
Question 3
To investigate the effect of concentration on a reaction rate, a student measured 100 cm³ of a 0.10 M solution of sodium thiosulfate into a conical flask, added 10 c... show full transcript
Worked Solution & Example Answer:To investigate the effect of concentration on a reaction rate, a student measured 100 cm³ of a 0.10 M solution of sodium thiosulfate into a conical flask, added 10 cm³ of 1.0 M hydrochloric acid, and then placed the flask on top of a cross on a sheet of white paper as shown in the diagram - Leaving Cert Chemistry - Question 3 - 2002
Step 1
a) Identify the pale yellow precipitate that obscured the cross on the sheet of paper.
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Answer
The pale yellow precipitate that obscured the cross on the sheet of paper is sulfur (sulphur), which forms as a byproduct of the reaction between sodium thiosulfate and hydrochloric acid.
Step 2
b) Describe the procedure for preparing the 0.08 M solution of sodium thiosulfate from the 0.10 M solution.
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Answer
To prepare the 0.08 M solution of sodium thiosulfate, first measure 80 cm³ of the 0.10 M sodium thiosulfate solution using a graduated cylinder. Then, add distilled water to bring the total volume to 100 cm³. This will dilute the concentration accordingly.
Step 3
c) Plot a graph to show the relationship between the initial rate of this reaction (1/time) and the concentration of sodium thiosulfate.
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On the x-axis, plot the concentration of sodium thiosulfate (M).
On the y-axis, plot the rate of reaction (1/time) in min−1.
Plot the points for the concentration and corresponding rates:
(0.08, 0.50)
(0.06, 0.43)
(0.04, 0.32)
(0.02, 0.16)
Connect the points with a straight line passing through the origin.
Step 4
d) Use the graph to determine how long it would take for the cross on the sheet of paper to become obscured in the reaction of the 0.05 M sodium thiosulfate solution.
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Answer
Using the graph, if a concentration of 0.05 M sodium thiosulfate is interpolated, it corresponds to a rate of approximately 0.20 min−1. The time taken for the cross to become obscured can be calculated by finding the reciprocal:
ext{Time} = rac{1}{ ext{Rate}} = rac{1}{0.20} = 5 ext{ minutes}.
Step 5
e) Explain why the reciprocal of the time (1/time) may be used as a measure of the initial rate of the reaction.
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Answer
The reciprocal of the time (1/time) provides an indication of the rate at which the reaction occurs. As the concentration of the reactants increases, the time taken for the observable change (the obscuring of the cross) decreases. Thus, a shorter time corresponds to a faster reaction rate, meaning that 1/time is a valid measure of the initial rate.
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