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How many iron atoms should be consumed daily to meet the recommended daily intake of iron in the diet of 0.014 g? - Leaving Cert Chemistry - Question e - 2007

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How many iron atoms should be consumed daily to meet the recommended daily intake of iron in the diet of 0.014 g?

Worked Solution & Example Answer:How many iron atoms should be consumed daily to meet the recommended daily intake of iron in the diet of 0.014 g? - Leaving Cert Chemistry - Question e - 2007

Step 1

Calculate the number of moles of iron in 0.014 g

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Answer

To find the number of moles, we use the formula:

n=mMn = \frac{m}{M}

where:

  • (n) is the number of moles,
  • (m = 0.014 , \text{g}) (mass of iron), and
  • (M = 56 , \text{g/mol}) (molar mass of iron).

Plugging in the values:

n=0.014g56g/mol=2.5×104moln = \frac{0.014 \, \text{g}}{56 \, \text{g/mol}} = 2.5 \times 10^{-4} \, \text{mol}

Step 2

Convert moles of iron to number of atoms

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Answer

To convert moles to the number of atoms, we use Avogadro's number, which is approximately (6.022 \times 10^{23} , \text{atoms/mol}).

Using the formula:

N=nNAN = n \cdot N_A

where:

  • (N) is the number of atoms,
  • (n = 2.5 \times 10^{-4} , \text{mol}), and
  • (N_A = 6.022 \times 10^{23} , \text{atoms/mol}).

Calculating:

N=2.5×104mol×6.022×1023atoms/mol1.5×1020atomsN = 2.5 \times 10^{-4} \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 1.5 \times 10^{20} \, \text{atoms}

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