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Some of the blue pigment azurite used by an artist in a picture painted in 1600 has changed over the years into green malachite according to the following balanced equation - Leaving Cert Chemistry - Question (a) - 2017

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Some of the blue pigment azurite used by an artist in a picture painted in 1600 has changed over the years into green malachite according to the following balanced e... show full transcript

Worked Solution & Example Answer:Some of the blue pigment azurite used by an artist in a picture painted in 1600 has changed over the years into green malachite according to the following balanced equation - Leaving Cert Chemistry - Question (a) - 2017

Step 1

What mass of pure azurite contains 3.81 g copper?

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Answer

To determine the mass of pure azurite containing 3.81 g of copper, we first consider the molar mass of copper, which is approximately 63.55 g/mol. In azurite, which has the formula (Cu_2(CO_3)(OH)_2), there are 2 moles of copper per mole of azurite. Therefore, the mass of azurite corresponding to the copper content can be found using the ratio:

  1. Calculate moles of copper:

    Moles of copper=mass of coppermolar mass of copper=3.81g63.55g/mol0.0599 moles of copper\text{Moles of copper} = \frac{\text{mass of copper}}{\text{molar mass of copper}} = \frac{3.81 g}{63.55 g/mol} \approx 0.0599 \text{ moles of copper}

  2. Find the moles of azurite from moles of copper:

    Moles of azurite=0.0599 moles of copper20.02995 moles of azurite\text{Moles of azurite} = \frac{0.0599 \text{ moles of copper}}{2} \approx 0.02995 \text{ moles of azurite}

  3. Calculate the molar mass of azurite:

    The molar mass of azurite is approximately 344.5 g/mol.

  4. Calculate mass of azurite:

    Mass of azurite=moles of azurite×molar mass of azurite0.02995 moles×344.5g/mol10.31g\text{Mass of azurite} = \text{moles of azurite} \times \text{molar mass of azurite} \approx 0.02995 \text{ moles} \times 344.5 g/mol \approx 10.31 g

Thus, approximately 10.31 g of pure azurite contains 3.81 g of copper.

Step 2

Calculate the maximum mass of malachite that will eventually be formed from this mass of azurite?

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Answer

To calculate the maximum mass of malachite formed from the azurite, we use the balanced chemical equation:

2Cu2(CO3)(OH)2(s)+H2O(l)3CuCO3(OH)2(s)+CO2(g)2Cu_2(CO_3)(OH)_2 (s) + H_2O (l) \rightarrow 3CuCO_3(OH)_2 (s) + CO_2 (g)

  1. From the equation, 2 moles of azurite yield 3 moles of malachite. Therefore, the stoichiometric ratio of azurite to malachite is:

    32\frac{3}{2}

  2. We previously calculated that we have approximately 0.02995 moles of azurite. Hence, the moles of malachite produced can be calculated as follows:

    Moles of malachite=0.02995 moles of azurite×320.044925 moles of malachite\text{Moles of malachite} = 0.02995 \text{ moles of azurite} \times \frac{3}{2} \approx 0.044925 \text{ moles of malachite}

  3. Calculate the molar mass of malachite, which is approximately 221 g/mol:

    Mass of malachite=moles of malachite×molar mass of malachite0.044925 moles×221g/mol9.93g\text{Mass of malachite} = \text{moles of malachite} \times \text{molar mass of malachite} \approx 0.044925 \text{ moles} \times 221 g/mol \approx 9.93 g

Thus, a maximum of approximately 9.93 g of malachite will be formed.

Step 3

What is the volume, measured at s.t.p., of carbon dioxide that would be released from the painting in the formation of this mass of malachite?

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Answer

To calculate the volume of carbon dioxide released during the formation of malachite, we analyze the balanced equation:

2Cu2(CO3)(OH)2+H2O3CuCO3(OH)2+CO22Cu_2(CO_3)(OH)_2 + H_2O \rightarrow 3CuCO_3(OH)_2 + CO_2

From this equation, we see that 2 moles of azurite produce 1 mole of carbon dioxide when converting to malachite.

  1. Calculate the moles of malachite formed:

    From the previous calculation, we have 0.044925 moles of malachite.

    The moles of carbon dioxide released will be half of the moles of malachite:

    Moles of CO2=0.04492530.014975 moles of CO2\text{Moles of } CO_2 = \frac{0.044925}{3} \approx 0.014975\text{ moles}\text{ of } CO_2

  2. Use the molar volume of gas at standard temperature and pressure (s.t.p.), which is approximately 22.4 L/mol:

    Volume of CO2=0.014975 moles×22.4Lmol0.335L\text{Volume of } CO_2 = 0.014975 \text{ moles} \times 22.4 \frac{L}{mol} \approx 0.335 L

Thus, approximately 0.335 liters of carbon dioxide would be released.

Step 4

Suggest a way that further deterioration of the painting by this chemical reaction could be prevented or delayed.

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Answer

To prevent or delay further deterioration of the painting caused by the reaction converting azurite to malachite, it is recommended to:

  • Keep it dry and in a low humidity environment: Moisture can facilitate the chemical reaction, so keeping the painting in a controlled environment will help slow down the process.
  • Use waterproof varnish (coating): Applying a protective coating can limit exposure to moisture and prevent chemical reactions, ensuring the conservation of the painting.
  • Protect from heat: Excessive heat can also accelerate deterioration, so keeping the painting in a stable temperature environment is essential.

By taking these measures, the longevity of the artwork can be maintained.

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